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-Dominant- [34]
2 years ago
10

If the side lengths of a cube are 15 feet, what is the correct way to write the expression to represent the volume of the cube i

n exponential form?
A 15 ⋅ 15 ⋅ 15
B 15 ⋅ 3
C 315
D 153
Mathematics
1 answer:
Oksi-84 [34.3K]2 years ago
5 0

Answer:

D

Step-by-step explanation:

A cube is something that has the same length on all sides, so therefore, multiplying one of the side lengths by 3 gets you the answer.

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Make d the subject of the formula h = d/3 + 2​
Thepotemich [5.8K]
First what you would have to do is distribute the reciprocal to the (d/3 + 2) and the d/3 is canceled out. You are left with h=6/d. When you put the h over 1 in a fraction, it stays the same. Like in trig, you switch the d and the h and you have d/1=6/h.

d=6/h
4 0
2 years ago
IS THIS CORRECT!!!????
yanalaym [24]
So if it has to be simplified, there is only one answer if all of it is positive but it has a solution to do with minus numbers which is -2 (-x-2)
8 0
3 years ago
Bryan cut two peaches that were the same size for lunch. he cut one peach into fourths and the other into sixths. bryan ate 3/4
lubasha [3.4K]
3/4 and 5/6
Now, you have to find the common denominator to compare the two fractions properly. Let’s see... 12 can be divided by both 4 and 6. So we’re going to convert both denominators to 12.

3*3= 9 and 4*3=12 so 3/4 = 9/12

5*2= 10 and 6*2=12 so 5/6 = 10/12

Bryan’s brother ate more peach.
4 0
2 years ago
I really need this answered so I can understand how to do the rest.
qwelly [4]

Answer:

B

Step-by-step explanation:

We can write

4=\sqrt{\frac{3v}{3.14*8}}\\4^2=\frac{3v}{25.12}\\16*25.12=3v\\401.92=3v\\133.9733333333333=v

4 0
2 years ago
M is a degree 3 polynomial with m ( 0 ) = 53.12 and zeros − 4 and 4 i . Find an equation for m with only real coefficients (i.E.
Nitella [24]

Answer:

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

Step-by-step explanation:

Given that M is a polynomial of degree 3.

So, it has three zeros.

Let the polynomial be

M(x) =a(x-p)(x-q)(x-r)

The two zeros of the polynomial are -4 and 4i.

Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.

Then,

M(x)= a{x-(-4)}(x-4i){x-(-4i)}

      =a(x+4)(x-4i)(x+4i)

      =a(x+4){x²-(4i)²}      [ applying the formula (a+b)(a-b)=a²-b²]

      =a(x+4)(x²-16i²)

      =a(x+4)(x²+16)      [∵i² = -1]

      =a(x³+4x²+16x+64)

Again given that M(0)= 53.12 . Putting x=0 in the polynomial

53.12 =a(0+4.0+16.0+64)

\Rightarrow a = \frac{53.12}{64}

      =0.83

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

5 0
3 years ago
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