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Semenov [28]
3 years ago
7

Evaluate the determinant for the following matrix: Please help !!!

Mathematics
1 answer:
Step2247 [10]3 years ago
5 0
The answer would be A
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If a * b + 5 *a + 3 * b + 15= 24 and a+ 3 =6 then what is the value of a+b​
Semmy [17]

Answer:

a +b = 2

Step-by-step explanation:

a +3 = 6

    a = 6 -3

   a = 3

Plugin  a =3 in the equation,

a*b +5*a +3*b + 15 = 24

3b + 5*3 + 3b + 15 = 24

3b + 15  + 3b + 15 = 24      {combine like  terms}

3b + 3b + 15 + 15 = 24

             6b  + 30  = 24           {Subtract 30 from both sides}

                       6b = 24 -30

                      6b = -6               {divide both sides by 6}

                         b = -6/6

b = -1

a + b = 3 + ( -1)

         = 2

7 0
3 years ago
Claire is shopping at a shoe store. The store is having a sale and discounting all shoes by 35% of the marked price. She decides
castortr0y [4]

999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999

7 0
3 years ago
The sample space for a roll of two number cubes is shown in the table.
katen-ka-za [31]
I think its C but I'm not 100% sure
5 0
3 years ago
Read 2 more answers
The point (-3,-1) is the midpoint of (x,y) and (5,4). Find the point (x,y).
nirvana33 [79]

Answer:

(-11, -6)

Step-by-step explanation:

Find the distance between the midpoint, (-3, -1) and (5, 4). This can be calculated by finding the difference between the x coordinates and y coordinates.

-3 - 5 = -8 (distance between x coordinates)

-1 - 4 = -5 (distance between y coordinates)

Find the point (x, y) by subtracting 8 from the midpoint's x value, and then subtracting 5 from the midpoint's y value.

-3 - 8 = -11

-1 - 5 = -6

So, the point (x, y) is (-11, -6)

4 0
3 years ago
Write the equation of the conic section with the given properties:
timurjin [86]

Answer:

\frac{x^2}{64} + \frac{y^2}{25} =1

Step-by-step explanation:

An ellipse with vertices (-8, 0) and (8, 0)

Distance between two vertices = 2a

Distance between (-8,0) and (8,0) = 16

2a= 16

so a= 8

Vertex is (h+a,k)

we know a=8, so vertex is (h+8,k)

Now compare (h+8,k) with vertex (8,0) and find out h and k

h+8 =8, h=0

k =0  

a minor axis of length 10.

Length of minor axis = 2b

2b = 10

so b = 5

General formula for the equation of horizontal ellipse is

\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b} =1

a= 8 , b=5 , h=0,k=0. equation becomes

\frac{(x-0)^2}{8^2} + \frac{(y-0)^2}{5} =1

\frac{x^2}{64} + \frac{y^2}{25} =1

5 0
3 years ago
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