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prisoha [69]
3 years ago
13

It takes Dariya 35 seconds to download 5 songs from the Internet. How can the number of seconds it would take Dariya to download

7 songs at this rate be determined?
Mathematics
2 answers:
Alex73 [517]3 years ago
8 0
By finding the unit rate and multiplying it by 7
GalinKa [24]3 years ago
5 0

Answer:

C

Step-by-step explanation: Here's a fraction equivalent to

35/5 songs ÷ 7 songs. We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 7. 35/5 divided by 7= 7 songs divided by 7. 5/5= 1 song 5/5= songs = 5/5 songs per song so C is you final answer

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Question 8<br> What is (4x - 5)(6x + 5) expressed as a trinomial?
erica [24]

Answer:

24x^2 -10x - 25

Step-by-step explanation:

24x^2 + 20x - 30x - 25

24^2 -10x - 25

8 0
3 years ago
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Anyone know this answer?
damaskus [11]
La of sine:

sinC/c = sinB/b==> sin  37°/8 = sin B/12 ==> sin B = 0.903


arcsinB or sin⁻¹ B = 64.5°, & sin (B°) = sin (180° - B°), then

sin(64.5) = sin(180°-64.5°) ==> B = 64.5° or 115.5°
6 0
3 years ago
Ryan has a school bag. He has 6 books, of which 2 are math books. What is the probability that a randomly selected book will be
Pavel [41]

1/3

2 of the books are math books and there are 6 books. This is 2/6. Now, divide both sides of the fraction by 2 to simplify it. This gives you a final answer of 1/3.

6 0
3 years ago
Ten engineering schools in the United States were surveyed. The sample contained 250 electrical engineers, 80 being women; 175 c
steposvetlana [31]

Answer:

There is a significant difference between the two proportions.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for difference between population proportions is:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

Compute the sample proportions as follows:

\hat p_{1}=\frac{80}{250}=0.32\\\\\hat p_{2}=\frac{40}{175}=0.23

The critical value of <em>z</em> for 90% confidence interval is:

z_{0.10/2}=z_{0.05}=1.645

Compute a 90% confidence interval for the difference between the proportions of women in these two fields of engineering as follows:

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

     =(0.32-0.23)\pm 1.645\times\sqrt{\frac{0.32(1-0.32)}{250}+\frac{0.23(1-0.23)}{175}}\\\\=0.09\pm 0.0714\\\\=(0.0186, 0.1614)\\\\\approx (0.02, 0.16)

There will be no difference between the two proportions if the 90% confidence interval consists of 0.

But the 90% confidence interval does not consists of 0.

Thus, there is a significant difference between the two proportions.

4 0
3 years ago
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lesya692 [45]

Multiplying by 10 can be thought of as just adding a 0 to the right end of a number. If you have 2 and multiply it by 10, you get 20. For 1,234, you get 12,340. If you have 98,765, you can 987,650. Same thing applies for 100, 1000, 10000, ...., and so on. It moves it over depending on the number of 0's there are in the number. If it is 100, it will move two 0's over. For example, if you multiply 45 by 100, you get 4,500. The two zeros from 100 moved to the right side of the 45 to get 4500.

6 0
3 years ago
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