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3 years ago

Help help me help help plz help help

Mathematics

1 answer:

Drupady [299]3 years ago

8 0

Answer:

6 1/6 (i think )

substitute 4 in for a, -5 for b and -7 for c

(4+ 2 * - 7 * - 5)/3 * 4

3*4 = 12

4+2 * - 7 * - 5) / 12

-7 * - 5 = 35 (same sign so positive)

(4+ 2* 35)/12

2*35 = 70 and 70+4 = 74.

74/12 is what we have, and we can simplify this to 37/6 by dividing both the numerator and denominator by 2. now we convert to mixed fraction and get 6 1/6.

Step-by-step explanation:

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No. The 10% commission will double to 20%,
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4 years ago

Read 2 more answers

SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!

Sloan [31]

ANSWER

$P-G = 11{w}^{4} - 5 {w}^{2} {z}^{2} - 4z^{4}$

EXPLANATION

The given polynomials are:

$G = - 3 {w}^{4} + 2 {w}^{2} {z}^{2} + 5z^{4}$

and

$P = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4}$

We want to subtract these two polynomials.

$P-G = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4} - (- 3 {w}^{4} + 2 {w}^{2} {z}^{2} + 5z^{4} )$

Expand the right hand side to obtain:

$P-G = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4} + 3 {w}^{4} - 2 {w}^{2} {z}^{2} - 5z^{4}$

Group the similar terms:

$P-G = 8 {w}^{4} + 3 {w}^{4}- 3{w}^{2} {z}^{2} - 2 {w}^{2} {z}^{2} - 5z^{4} + z^{4}$

Combine the similar terms to get:

$P-G = 11{w}^{4} - 5 {w}^{2} {z}^{2} - 4z^{4}$

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3 years ago

If s varies inversely as t^2, and s = 10 when t=2, find s when t is 10.

shepuryov [24]

We apply our knowledge in variation.

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3 years ago

What number is being factored in this factor tree? A.72 B.180 C.216 D.324

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3 years ago

The standard deviation of a sample taken from population A is 17.6 for a sample of 25.

lawyer [7]

Answer:

The standard deviation of the sample mean differences is _5.23_

Step-by-step explanation:

We have a sample of a population A and a sample of a population B.

For the sample of population A, the standard deviation $\sigma_A$ is

$\sigma_A = 17.6$

The sample size $n_A$ is:

$n_A = 25$ .

For the sample of population B, the standard deviation $\sigma_B$ is

$\sigma_B = 21.2$

The sample size $n_B$ is:

$n_B = 30$ .

Then the standard deviation for the difference of means has the following form:

$\sigma=\sqrt{\frac{\sigma_A^2}{n_A}+\frac{\sigma_B^2}{n_B}}$

Finally

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4 years ago