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Trava [24]
3 years ago
5

A teacher wants to buy 9 boxes of granola bars for a school trip. Each box usually costs $7, but many grocery stores are having

a sale on granola bars this week. Different stores are selling boxes of granola bars at different discounts.
Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

well I think the question's not complete but if that's the question then 9 boxes would cost about $63 dollars. since some stores have a sale, you should add the word 'about' or 'around' with the answer. hope it was helpful ))

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2/3 + 3/4 + 4/2. If a fraction appears in your answer, it should be in simplified form.
V125BC [204]
We must first make each fraction have a common denominator, this will be 12
2/3 * 4/4 = 8/12
3/4 * 3/3 = 9/12
4/2 * 6/6 = 24/12
we can then add the numerators of each fraction
8 + 9 + 24 = 41
so our answer is 41/12
we can not simplify any further and thus get
41/12
5 0
2 years ago
A math professor notices that scores from a recent exam are normally distributed with a mean of 61 and a standard deviation of 8
Alexeev081 [22]

Answer:

a) 25% of the students exam scores fall below 55.6.

b) The minimum score for an A is 84.68.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 61 and a standard deviation of 8.

This means that \mu = 61, \sigma = 8

(a) What score do 25% of the students exam scores fall below?

Below the 25th percentile, which is X when Z has a p-value of 0.25, that is, X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 61}{8}

X - 61 = -0.675*8

X = 55.6

25% of the students exam scores fall below 55.6.

(b) Suppose the professor decides to grade on a curve. If the professor wants 0.15% of the students to get an A, what is the minimum score for an A?

This is the 100 - 0.15 = 99.85th percentile, which is X when Z has a p-value of 0.9985. So X when Z = 2.96.

Z = \frac{X - \mu}{\sigma}

2.96 = \frac{X - 61}{8}

X - 61 = 2.96*8

X = 84.68

The minimum score for an A is 84.68.

8 0
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Kisachek [45]

Answer:

The answer is c!

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Solve for x: -6x - 2 = 40
julia-pushkina [17]
<span>-6x - 2 = 40
-6x = 42
x = -7
..................</span>
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