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kvv77 [185]
3 years ago
6

A fruit company delivers its fruit in Two types of boxes large and small a delivery of 7 large boxes and 9 small boxes has a tot

al weight of 274 kilograms a delivery of 5 large boxes and 3 small boxes has a total weight of 141 kilograms how much does each type of box weight
Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

i don't have an answer sorry.

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t= -3.7

Step-by-step explanation:

1. 5( t+3)= -3.5

2. 5t+15= -3.5

3. 5t= -18.5

4. t= -3.7

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Step-by-step explanation:

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3. Rewrite the expression as simply as you can:<br> 3x + 11y - 2x - 4y
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x+7y

Step-by-step explanation:

First off, lets split the question into both x and y.

3x - 2x for the x

11y - 4y for the y

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The answer to the question

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3 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
2 years ago
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