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3 years ago

I need help ASAP will mark you the brainliest

Mathematics

1 answer:

Vadim26 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

<DCE = BCA (vertical angles are congruent)

DC corresponds to CB,

DC/CB = 15/5 = 3

EC corresponds to CA,

EC/CA = 12/4 = 3

Thus, two sides in ∆ABC are proportional to two corresponding sides in ∆EDC, and also, the included angle in ∆ABC and ∆EDC are congruent to each other. Therefore, based on the SAS Similarity Theorem, ∆ABC and ∆EDC are similar.

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Find the domain of the graphed function?

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4 years ago

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If the area of a square is 36 inches what is the length of one side?

Pavel [41]

To find the length of a square given the area, we just need to take the square root of the area given. The sqrt of 36 is 6, so each side is 6 inches. :)

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3 years ago

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What is y=\dfrac{2}{3}x+4y=

lara [203]

Answer:

$12y+x-12=0$

Step-by-step explanation:

If I'm not mistaken by the question, we have

$x+4y=\dfrac{2}{3}x+4$

Multiply through by the LCM of all the denominators to clear the fractions. Since we have only one fraction, we multiply through by its LCM (3)

$3\timesx+3\times4y=3\times\dfrac{2}{3}x+3\times4$

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Putting all terms on the LHS (left hand side) and evaluating,

$12y+x-12=0$

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3 years ago

Solve the equation <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B3%7D%7B4%7D%20%3D8" id="TexFormula1" title="\frac{x+3}{4} =8"

fiasKO [112]

Answer:

Step-by-step explanation:

Multiply by 4

so x+3=8*4

x+3=32

-3. -3

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3 years ago

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Suppose that vehicles taking a particular freeway exit can turn right (R), turn left (L), or go straight (S). Consider observing

Basile [38]

Answer:

A={RRR,SSS,LLL}

B={RSL,SLR,LRS,RLS,SRL,LSR}

C={RRL,RLR,LRR,RRS,SRR,RSR}

D={RRL, RRS, RLR, RLL, RSR, RSS, LRR, LRL, LLR, LLS, LSL, LSS, SRR, SRS, SLL, SLS, SSR, SSL}

D'={RRR, RLS, RSL, LRS, LLL, LSR, SRL, SLR, SSS}

Step-by-step explanation:

Sample space=S= {RRR, RRL, RRS, RLR, RLL, RLS, RSR, RSL, RSS, LRR, LRL, LRS, LLR, LLL, LLS, LSR, LSL, LSS, SRR, SRL, SRS, SLR, SLL, SLS, SSR, SSL, SSS}

Let A be the event that all three vehicles go in same direction. It means that the all three vehicles go to right or left or straight. Thus, event A can be represented as

A={RRR,SSS,LLL}

Let B be the event that all three vehicles go in different direction. It means that the three vehicles can go to

1. Right, Straight, Left

2. Straight, Left, Right

3. Left, Right, Straight

4. Right, Left, Straight

5. Straight, Right, Left

6. Left, Straight, Right

Thus, event B can be represented as

B={RSL,SLR,LRS,RLS,SRL,LSR}

Let C be the event that exactly two of three vehicles turn right. It means that the three vehicles can go to

1. Right, Right , Left

2. Right , Left, Right

3. Left, Right, Right

4. Right, Right , Straight

5. Straight, Right,Right

6. Right , Straight, Right

Thus, event C can be represented as

C={RRL,RLR,LRR,RRS,SRR,RSR}

Let D be the event that exactly two of three vehicles go in same direction. It means that the three vehicles can go to

1. Right, Right, Left

2. Right, Right, Straight

3. Right, Left, Right

4. Right, Left, Left

5. Right, Straight, Right

6. Right, Straight, Straight

7. Left, Right, Right

8. Left, Right, Left

9. Left, Left, Right

10. Left, Left, Straight

11. Left, Straight, Left

12. Left, Straight, Straight

13. Straight, Right, Right

14. Straight, Right, Straight

15. Straight, Left, Left

16. Straight, Left, Straight

17. Straight, Straight, Right

18.Straight,Straight, Left

Thus, event D can be represented as

D={RRL, RRS, RLR, RLL, RSR, RSS, LRR, LRL, LLR, LLS, LSL, LSS, SRR, SRS, SLL, SLS, SSR, SSL}

D'=S-D= {RRR, RRL, RRS, RLR, RLL, RLS, RSR, RSL, RSS, LRR, LRL, LRS, LLR, LLL, LLS, LSR, LSL, LSS, SRR, SRL, SRS, SLR, SLL, SLS, SSR, SSL, SSS} -{RRL, RRS, RLR, RLL, RSR, RSS, LRR, LRL, LLR, LLS, LSL, LSS, SRR, SRS, SLL, SLS, SSR, SSL}

D'={RRR, RLS, RSL, LRS, LLL, LSR, SRL, SLR, SSS}

8 0

3 years ago