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ludmilkaskok [199]
3 years ago
13

An insurance company sells one-fourth as many preferred policies as standard policies and one-fourth as many ultra-preferred pol

icies as preferred policies. All policies are classified as standard, preferred, or ultra-preferred. Calculate the probability that a randomly selected policy is ultra-preferred.
Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

4.7619%

Step-by-step explanation:

Let's suppose the insurance company sells 16 standard policies.

For every 16 standard policies sold, the company sells 1/4 x 16, or 4, preferred policies.

For every 4 preferred policies sold, the company sells 1/4 x 4, or 1, ultra-preferred policy.

Therefore, for every ultra-preferred policy sold, the company sells:

16+4+1=21 total policies

So the probability of any 1 random policy selected being ultra-preferred is 1/21, or 4.7619% ....................

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Answer:

The solution for y = -1.

Step-by-step explanation:

Given:

2x\ +\ 7y\ =\ 1    ....(1)

2x\ -\ 4y\ =\ 12  ....(2)

So, to solve for y, first we solve for x in equation (2):

2x-4y=12

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Dividing both sides by 2,

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2x+7y=1

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Dividing both sides by 11,

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2 years ago
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3 years ago
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lara31 [8.8K]

Answer:

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Rewrite the equation 4x + 4y = 20 in slope-intercept form.
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<span> 4x + 4y = 20
If I'm not mistakened, this is in it's standard form. 
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