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3 years ago

The equation 22 + 0.15p =c

1 answer:

8 0

You have inadvertently left out some of the instructions for this problem.

22 + 0.15p =c could be solved for p; that's one thing you could do now.

Subtracting 22 from both sides, 0.15p = c - 22

Dividing both sides by 0.15, p = (c-22)/0.15 , or p = (20/3)(c-22).

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How do you turn 21\28 in to 75 \100

Sonbull [250]

75% * 28 =
(75 : 100) * 28 =
(75 * 28) : 100 =
2,100 : 100 =
= 21

4 0

4 years ago

Steph,andra,emily,and becca are planning a road trip from their hometown to san antonio

morpeh [17]

Answer:

a. Emily should begin her turn as the third driver at point (1, -0.5).

b. Emily's turn to drive end at point (-2.5, -3.75).

Step-by-step explanation:

Let assume that the group of girls travels from their hometown to San Antonio in a straight line. We know that each location is, respectively:

Hometown

$H(x,y) = (8,6)$

San Antonio

$T(x,y) = (-6,-7)$

Then, we can determine the end of each girl's turn to drive by the following vectorial expression based on the vectorial equation of the line:

Steph

$S(x,y) = H(x,y) + \frac{1}{4}\cdot [T(x,y)-H(x,y)]$ (1)

$S(x,y) = (8,6) + \frac{1}{4}\cdot [(-6,-7)-(8,6)]$

$S(x,y) = (8,6) +\frac{1}{4}\cdot (-14,-13)$

$S(x,y) = (4.5,2.75)$

Andra

$A(x,y) = H(x,y) + \frac{2}{4}\cdot [T(x,y)-H(x,y)]$ (2)

$A(x,y) = (8,6) + \frac{2}{4}\cdot [(-6,-7)-(8,6)]$

$A(x,y) = (8,6)+\frac{2}{4}\cdot (-14,-13)$

$A(x,y) =(1, -0.5)$

Emily

$E(x,y) = H(x,y) + \frac{3}{4}\cdot [T(x,y)-H(x,y)]$ (3)

$E(x,y) = (8,6) + \frac{3}{4}\cdot [(-6,-7)-(8,6)]$

$E(x,y) = (8,6)+\frac{3}{4}\cdot (-14,-13)$

$E(x,y) = (-2.5, -3.75)$

a. If the girls take turns driving and each girl drives the same distance, at what point should they stop from Emily to begin her turn as the third driver?

Emily's beginning point is the Andra's stop point, that is, $A(x,y) =(1, -0.5)$ .

Emily should begin her turn as the third driver at point (1, -0.5).

b. At what point does Emily's turn to drive end?

Emily's turn to drive end at point (-2.5, -3.75).

7 0

3 years ago

In the Itty Bitty High School, there are 85 students. There are 27 students who take French, 51 who take Geometry and 38 who tak

andrew-mc [135]

Answer:

58 students

Step-by-step explanation:

Given

$Total = 85$

$French = 27$

$Geometry = 51$

$History = 38$

$None = 5$

$All = 2$

Required

Students that take only 1 subjects

The attached image illustrates the question.

For French only (x), we have:

$x + 7 -2+10-2+2=27$

$x + 15=27$

Collect like terms

$x =- 15+27$

$x =12$

For Geometry only (y), we have:

$y+10-2+15-2+2=51$

$y+23=51$

Collect like terms

$y=-23+51$

$y=28$

For History only (z), we have:

$z +15-2+7-2+2=38$

$z +20=38$

Collect like terms

$z =-20+38$

$z =18$

Students with one subject is then calculated as:

$1\ subject = x+y+z$

$1\ subject = 12 + 28 + 18$

$1\ subject = 58$

5 0

3 years ago

The number of households without a computer at home in 2009 was closest to A)801000 B)1153000 C)1737000 D)3433000 E)4017000

bagirrra123 [75]

Answer:

B) 1153000

Step-by-step explanation:

Given

See attachment

Required

Number of households without computer in 2009

From the attachment, we have:

$n=5170000$ --- survey

$p = 22.3\%$ --- proportion without computer

So, the actual number is:

$Number = p * n$

$Number = 22.3\% * 5170000$

$Number = 1152910$

$Number \approx 1153000$

Hence: (B) is correct

7 0

3 years ago

Isolate the variable 4m=92

const2013 [10]

Simplifying 4x = 92 Solving 4x = 92 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Divide each side by '4'. x = 23 Simplifying x = 23

5 0

3 years ago