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goblinko [34]
2 years ago
9

Which division problem does the model below show? 4 fraction bars. The fraction bars are labeled 1 and each have 6 boxes underne

ath labeled one-sixth. 4 divided by one-sixth = 24 4 divided by one-sixth = 12 24 divided by one-sixth = 4 12 divided by one-sixth = 4
Mathematics
2 answers:
Leya [2.2K]2 years ago
5 0

Answer:

I say its a because thanks to the person who answered before me is right.

Step-by-step

Ksivusya [100]2 years ago
4 0

Answer:

4 divided by one-sixth = 2

Step-by-step explanation:

Given 4fraction bars

If each fraction bars has 6boxes, then we can get the total boxes for 4fractiom bars as shown;

1 fraction bars = 6boxes

4fraction bars = x

Cross multiply

1 × x = 4×6

x = 4× 6/1

x = 4 ÷ 1/6

Hence the division problem that modelled the expression is 4 ÷ 1/6

4÷1/6 = 4×6/1

4÷1/6 = 24

Option A is correct

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Solve for y in terms of x. 2/3 y - 4 = x
Nastasia [14]

Answer:

y = 3/2x + 6

Step-by-step explanation:

2/3 y - 4 = x

2/3y = x + 4

y = 3/2 * (x + 4)

y = 3/2x + 6

3 0
2 years ago
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A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation
Alexxx [7]
Ok

y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate

set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}
a=-0.04
b=8.3
c=4.3
x=\frac{-8.3+/- \sqrt{8.3^{2}-4(-0.04)(8.3)} }{2(-0.04)}
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7 0
3 years ago
Which number is greater and by how much: A decreased by 50% and then increased by 50% of the result
cricket20 [7]

Answer:

the original number is greater

Step-by-step explanation:

1. let 1x be your starting number

2. therefore, 0.5 * 1x = 0.5x ( amount after you decreased it by 50%)

3. then increase: 0.5x * 1.5 = 0.75x (amount after you increased it by 50%)

4. 0.75x < 1x (this means that the original number is larger than the one you decreased and then increased)

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In how many ways could the letters in
Artyom0805 [142]

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4 0
3 years ago
Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

6 0
3 years ago
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