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Bumek [7]
2 years ago
14

1. What is the standard form for the following: 3x^2 - 4x + 6x^5 + 10x^3 - 8

Mathematics
1 answer:
Mrrafil [7]2 years ago
6 0

Answer:

how this helps

Step-by-step explanation:

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Ummm can someone plsss help, i need this to bring my grade up!!?
artcher [175]

Answer:

I would say it would also be 64 degrees because if you flip the HGJ to the IJG it would be the same! Hope this helps

:)

8 0
3 years ago
Read 2 more answers
Can somebody please help me with question b please?
snow_tiger [21]
\bf A=
\begin{bmatrix}
-2&0\\1&3
\end{bmatrix}\qquad B=
\begin{bmatrix}
1&0&3\\-1&3&0
\end{bmatrix}\\\\
-----------------------------\\\\
AB=
\begin{bmatrix}
(-2\cdot 1)+(0\cdot -1)&(-2\cdot 0)+(0\cdot 3)&(-2\cdot 3)+(0\cdot 0)\\\\
(1\cdot 1)+(3\cdot -1)&(1\cdot 0)+(3\cdot 3)&(1\cdot 3)+(3\cdot 0)
\end{bmatrix}

as you notice above, is the first-row components from A, multiplying all the columns subsequently on B, and you add the products of that row, that gives you one component on the AB matrix

in the one above, we end up with a 2x3 AB matrix
4 0
3 years ago
Preform the indicated operation and express the answer in simplest radical form
tigry1 [53]

hello

the question here is

3\sqrt[]{7}(14-4\sqrt[]{56})

step 1

multiply through the bracket by the coeffiecient

\begin{gathered} 3\sqrt[]{7}(14-4\sqrt[]{56}) \\ (3\sqrt[]{7}\times14)-(3\sqrt[]{7}\times4\sqrt[]{56}) \\ (14\times3\sqrt[]{7})-3\sqrt[]{7}\times4\sqrt[]{4\times14} \\ (42\sqrt[]{7})-3\sqrt[]{7}\times8\sqrt[]{14} \\ (42\sqrt[]{7})-\lbrack(3\times8)\sqrt[]{7\times14} \\ 42\sqrt[]{7}-24\sqrt[]{98} \end{gathered}\begin{gathered} 42\sqrt[]{7}-24\sqrt[]{49\times2} \\ 42\sqrt[]{7}-24\times7\sqrt[]{2} \\ 42\sqrt[]{7}-168\sqrt[]{2} \end{gathered}

5 0
1 year ago
If 8^x=27, then what is 4^(2x-3)?
Leviafan [203]

Answer:

Step-by-step exExplanation:

4

x

=

7

4

−

2

x

=

1

4

2

x

=

1

(

4

x

)

2

=

1

(

7

)

2

=

49

7 0
2 years ago
What are the solutions to this equation?<br> 7x2 − 28 = 0
valentina_108 [34]

Answer:

x = 2 or x = -2

Step-by-step explanation:

7x^2 - 28 = 0

7x^2 = 28

x^2 = 28/7 = 4

x = root(4)  or  x = -root(4)

x = 2 or x = -2

8 0
2 years ago
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