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bija089 [108]
3 years ago
7

!!!!!!!!!!!!help me

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

Step-by-step explanation:

i'll do a few of them

1)   one inch plus a half inch plus an eighth inch plus a sixteenth inch

     1 + 1/2 + 1/8 + 1/16         read the tick marks

     1 + 8/16 + 2/16 + 1/16    find a common denominators

     1 and 11/16                    add the sixteenth numerator

2)

3)

4)  6 inch  plus an eighth inch plus a sixteenth inch

     6 +  1/8 + 1/16         read the tick marks

     6 + 2/16 +  1/16       find a common denominators

     6 and 3/16              add the sixteenth numerator

5)   nine inch plus a quarter inch plus an eighth inch

     9  + 1/4 + 1/8          read the tick marks

     9 + 2/8 + 1/8          find a common denominators

     9 and 3/8              add the sixteenth numerator

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A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

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3 years ago
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olga_2 [115]

Step-by-step explanation:

Let original price be x

Price after 40% discount is $201

Therefore

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x = 201 ÷ (40/100)

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Therefore, the original price is $502.5

Hope it helps :)

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Answer:

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Step-by-step explanation:

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