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Mumz [18]
3 years ago
8

Lesson 1: identify pairs of lines and angles draw two lines intersected by a transversal. label corresponding angles ∠1 and ∠2.

label alternate interior angles ∠3 and ∠4. label alternate exterior angles ∠5 and ∠6. label consecutive interior angles ∠7 and ∠8. label vertical angles ∠9 and ∠10. answers
Mathematics
2 answers:
liraira [26]3 years ago
7 0
Draw 2 lines horizontally then one angled line through them and go from bottom to top labeling the answer
 
Travka [436]3 years ago
6 0
Each number goes by tge side ??
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Which expressions are polynomials?
Oduvanchick [21]

Answer:


Step-by-step explanation:

Definition : The expression that can have constants (like 4), variables (like x or y) and exponents (like the 2 in y^{2}), that can be combined using addition, subtraction, multiplication and division, but no division by a variable and a variable's exponents can only be 0,1,2,3,... etc. and it can't have an infinite number of terms.

1. 6 + p

Being p be a variable this equation is polynomial

2.  x – 1

Since x-1 has variable and constant so according to definition it is a polynomial

3. 8x−z3

According to definition it is a polynomial

4 .5x^{2}-x\sqrt{}

Since has root so it is not a polynomial .


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Y- intercept of 6x-3y=24
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y- intercept (s) (0, -8)

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3 years ago
How many pounds are in 1 ton 1,600 ounces?
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Which answer is true
Veseljchak [2.6K]

\star=x\\\triangle=1\\\\\text{the equation:}\\\\5\star=5\triangle\\\\therefore\\\\5x=5\cdot1\\\\\boxed{5x=5}



Answer: D. 5x = 5

8 0
3 years ago
PLS HELP ASAP If -2 is added to each of the x and y intercepts of the line 3x + 2y = 6, find the new equation of the line
ella [17]

Answer:

3x + 2y = -4

Step-by-step explanation:

x intercept of the line occurs at y = 0

Given the equation 3x+2y = 6

3x+2(0) = 6

3x  = 6

x = 2

The x intercept is at (2, 0)

Adding -2 to each axis will give (2-2, 0-2) = (0, -2)

y intercept of the line occurs at x = 0

Given the equation 3x+2y = 6

3(0)+2y = 6

2y  = 6

y =3

The x intercept is at (0, 3)

Adding -2 to each axis will give (0-2, 3-2) = (-2, 1)

The new coordinates are (0, -2 and (-2, 1)

Using the point slope form of the equation y - y0 = m(x-x0)

slope m = y2-y1/x2-x1

m = 1-(-2)/-2-0

m = 1+2/-2

m = -3/2

Using m = -3/2 and (0, -2)

y - (-2) = -3/2(x-0)

y+2 = -3/2 x

2(y+2) = -3x

2y+4 = -3x

-3x-2y = 4

3x + 2y = -4

Hence the required equation is 3x + 2y = -4

7 0
2 years ago
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