An equilateral triangle has three 60 degree angles.
The altitude divides it into two 30 60 90 triangles.
The altitude is the "middle side" of such a triangle.
When that is the case, the middle side divided by the square root of 3 = the short side and multiplied by (2/sq root (3)) equals the hypotenuse.
The hypotenuse is the side of the equilateral triangle.
So, 6 * 2 / (sq root of 3) =
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6.9282032303
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Source:
http://www.1728.org/trig2.htm
Since BD bisects angle ABC, that means angle ABD and angle CBD are equal to each other. With that set up the equation to solve for x like this:
-4x+33 = 2x+81
-2x -2x
————————
-6x +33 = 81
-33 -33
————————
-6x = 48
————- (divide by -6)
-6
x = -8
Now substitute that to ABD
-4(-8) +33
32 +33
=65
here’s CBD
2(-8) + 81
-16 + 81
=65
Finally angle ABC will be double the amount of ABD or CBD so 65 times 2 is 130.
ANSWERS: (angles)
ABD and CBD: 65
ABC: 130
Answer:
88
Step-by-step explanation:
5GP= BP
2BNP= GNP
BP+BNP=333
GP+GNP=225
BNP= 333-BP
BNP= 333-5GP
GP= 225-GNP
GP= 225-2BNP
BNP=333-5(225-2BNP)
BNP=333-1125+10BNP
-9BNP=-792
BNP=88
Hope it helps :)
Mark Brainliest if possible.
Its R
you can just see in figure as square root of 50 is approximately around 7.07
Let the unknown variable be x.
5627x=41
x=41/5627
