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Andrew [12]
2 years ago
5

Is 2/5 greater than 2/3? ​

Mathematics
2 answers:
liubo4ka [24]2 years ago
5 0

Answer:

no because 2/3 is greater

GenaCL600 [577]2 years ago
5 0

Answer:

no

Step-by-step explanation:

2/5 and 2/3 can be turned into 6/15 and 10/15. you can clearly see 10/15 (2/3) is higher in value than 6/15.

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The following table shows the number of hours some high school students in two towns spend riding the bus each week:
katen-ka-za [31]

Hey there again,

The first step is to put the data in order, as shown in the diagram below


Five summaries of Town A

Lowest Value = 10

Lower Quartile,  = 16.5 (The value falls between 16 and 17)

Median,  = 25

Upper Quartile,  = 40 (The middle value between 38 and 42)

Highest value = 42


Five summaries of Town B

Lowest value = 0

Lower Quartile,  = 4 (The middle value between 0 and 8)

Median,  = 9

Upper Quartile,  = 20 (The middle value between 19 and 21)

Highest Value = 30

Hoped I Helped

8 0
3 years ago
Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e.
prohojiy [21]

Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

8 0
3 years ago
Which of the following shows the extraneous solution to the logarithmic equation below? log Subscript 3 Baseline (18 x cubed) mi
Mnenie [13.5K]

Answer:

C.) x= -4

Step-by-step explanation:

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C! youve got it dude !!!
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Goryan [66]

all students who attend 1 MS and 1 HS in Miami, FL.

This is because they only surveyed 1 ms and 1 hs


Good luck! please vote me brainliest

5 0
2 years ago
Read 2 more answers
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