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3 years ago

Please help me it would help a lot

Mathematics

2 answers:

nignag [31]3 years ago

7 0

4x-55 would be what’s ced
Bec 4x-5

Lyrx [107]3 years ago

6 0

Answer:

x=11°

<Bec = 33°

<Ced = 39°

Step-by-step explanation:

That's a right angle so it would be 90 degrees angle.

18+3x+4x-5=90

Lets simplify it to make it easier to work out by collecting like terms.

First all the variable 3x+4x=7x

Then the numbers 18+-5=13

13(-13)+7x = 90(-13)take away 13 from both sides

(Opposite operators EG, Add becomes subtract)

7x = 77 then divide 7 from both sides

x=11

Then work out

3x11=33 degrees

4x11=44-5=39 degrees

To double check 39+33+18=90 degrees

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BRAINLIEST WILL GIVE

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Answer:

Commutative

Step-by-step explanation:

because both sides contain 4.3 + g in any order.

6 0

3 years ago

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riadik2000 [5.3K]

Answer:

a) System of equations will be: $x+y=500\: and\:5x+2y=1789$

b) Number of adult tickets sold = 263

Number of students tickets sold = 237

Step-by-step explanation:

Let:

Number of adult tickets sold = x

Number of students tickets sold = y

As Marc sold total 500 tickets, the expression will be: $x+y=500$

Student tickets cost $2 and adult tickets cost $5. Marc's sales totalled $1,789.

The expression will be: $5x+2y=1789$

So, system of equations will be: $x+y=500\: and\:5x+2y=1789$

Solve the system to find value of x and y

Let:

$x+y=500--eq(1)\\5x+2y=1789--eq(2)$

Multiply equation 1 by 2 and subtract

$2x+2y=1000\\5x+2y=1789\\-\:\:\:-\:\:\:\:\:\:\:\:\:-\\------\\-3x=-789\\x=\frac{-789}{-3}\\x=263$

We get value of x = 263

Now finding value of y by putting value of x in eq(1)

$x+y=500\\263+y=500\\y=500-263\\y=237$

We get value of y = 237

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Number of students tickets sold = y = 237

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3 years ago

Find the length of x. Assume the triangles are similar.

gayaneshka [121]

Answer:

Step-by-step explanation:

Assuming the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{2.8}{x}$ = $\frac{2.4}{4.8}$ ( cross- multiply )

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3 years ago

Suppose Clare labels the books at a constant speed of s books per minute. Write an equation that represents the relationship bet

iragen [17]

Answer:

75 minutes

50 minutes

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Step-by-step explanation:

Complete question below:

Clare volunteers at a local library during the summer. Her work includes putting labels on 750 books.

How many minutes will she need to finish labeling all books if If she takes no breaks and labels:

a. 10 books a minute

b. 15 books a minute

Suppose Clare labels the books at a constant speed of books per minute. Write an equation that represents the relationship between her labeling speed and the number of minutes it would take her to finish labeling

Solution

a. 10 books a minute

Number of minutes to finish labelling all books at 10 books per minute = Total books / books labelled per minute

= 750 / 10

= 75 minutes

Number of minutes to finish labelling all books at 10 books per minute = 75 minutes

b. 15 books a minute

Number of minutes to finish labelling all books at 15 books per minute = Total books / books labelled per minute

= 750 / 15

= 50 minutes

Number of minutes to finish labelling all books at 15 books per minute = 50 minutes

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3 years ago

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worty [1.4K]

Answer:

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Step-by-step explanation:

1. so you add (3/12) + 1/12= 4/12

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