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2 years ago

Write the equation of the line that passes through the points (-8, -8) and

Mathematics

1 answer:

IgorLugansk [536]2 years ago

8 0

Mmkn nunuhjejdbdjdjdvdjdbdbjdcinfnff

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Will make brainliest if answered correctly

Komok [63]

Answer:

i think the answer is (B)

Step-by-step explanation:

The y value of a point where a vertical line intersects a graph represents an output for that input x value. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that x value has more than one output.

6 0

3 years ago

Read 2 more answers

Twenty-one people brought a chocolate cake to a community potluck dinner each cake was split into 8 slices how many slices of ch

dexar [7]

Answer:

168

Step-by-step explanation:

Multiply 21 by 8 so

21 × 8 = 168

6 0

3 years ago

Find the area of the shape shown below.

Tamiku [17]

Answer:

28 square units.

Step-by-step explanation:

Let us divide the shape into two rectangles and a right triangle. The resulting composite figure is attached.

As we see in the figure the area $A_T$ of the triangle is

$A_T= \frac{1}{2} (2)(4)=4\: units^2$ .

The area $A_{r1}$ of the bigger rectangle is (it's actually a square )

$A_{r1}=4*4=16\:units^2$ ,

and the area of the smaller rectangle is

$4*2 =8\:units^2$ .

Therefore, the total area $A_{tot}$ of the shape is

$A_{tot}= A_T+A_{r1}+A_{r2}$

$A_{tot}= 4\:units^2+16\:units^2+8\:units^2$

$\boxed{A_{tot}=28 \:units^2}$

5 0

3 years ago

Read 2 more answers

What is the value of x?<br> Enter your answer, as a decimal, in the box.

RideAnS [48]

Answer:

x = 67.5 ft

Step-by-step explanation:

In ΔNMP

∵ AB // NP

∴ m∠ MAB = m∠MNP

∴ m∠MBA = m∠MPN

∵ ∠M is a comman angle

∴ ΔMAB is similar to ΔMNP

∴ MA/MN = MB/MP

∵ MA = 71.5 - 22 = 49.5

∴ 49.5/71.5 = x/97.5

∴ x = $\frac{(49.5)(97.5)}{71.5}$ = 67.5

7 0

2 years ago

The position, x, of an object is given by the equation x = A + Bt +Ct2, where t refers to time. What are the dimensions of A, B,

Serjik [45]

Answer: Dimensions of A are of length [L]

Dimensions of B are of $LT^{-1}$

Dimensions of C are of $LT^{-2}$

Step-by-step explanation:

The given equation is

$x(t)=A+Bt+Ct^{2}$

Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid

Thus

Dimensions of A = [L]

Dimensions of Bt = [L]

$Bt=[L]\\\\$ $[B][T]=[L]$ $\\\\\therefore [B]=LT^{-1}$

Similarly

Dimensions of $Ct^{}2 = [L]$

$Ct^{2}=[L]\\\\[C][T]^{2}=[L]\\\\\therefore [C]=LT^{-2}$

4 0

2 years ago