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Nookie1986 [14]
3 years ago
13

Can someone help me with this? Please look at the top, write it in standard form.

Mathematics
1 answer:
bearhunter [10]3 years ago
4 0
11.  .0000003
12. 9050.

I'm not sure about 12,
but I do know 11 is correct.
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25-42 Differentiate the function.<br> 25. <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B5%7D%2B5%5E%7Bx%7D" id="TexFormula
natulia [17]

Answer:

<u>y'= 5x^4 + 5^x In(5)</u>

Step-by-step explanation:

<u>Differentiate</u><u> </u><u>with </u><u>Respect</u><u> </u><u>to</u><u> </u><u>x</u>

<u>f(</u><u>x)</u><u>'</u><u>=</u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>In(</u><u>5</u><u>^</u><u>x</u><u>)</u>

<u>f(</u><u>x)</u><u>'</u><u>=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>x </u><u>In(</u><u>5</u><u>)</u>

<u>with </u><u>respect</u><u> </u><u>to </u><u>x,</u><u> </u><u>we </u><u>have</u>

<u>y'=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>y </u><u>In(</u><u>5</u><u>)</u>

<u>y'=</u><u> </u><u>5</u><u>x</u><u>^</u><u>4</u><u> </u><u>+</u><u> </u><u>5</u><u>^</u><u>x</u><u> </u><u>In(</u><u>5</u><u>)</u>

8 0
2 years ago
35% of the original price of a phone is £78 what was the original price ?
Yakvenalex [24]

Answer:

222.86

Step-by-step explanation:

<h2><u>in order to solve this question you can create an equation :</u></h2>

35% * x = 78

where x is the original amount

in order to get x , you have to say :

78/ 35% = x

hence x = 222.8571...

to 2dp = 222.86

4 0
3 years ago
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