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mezya [45]
3 years ago
12

PLEASE I NEED TO TURN THIS IN TOMORROW I NEED HELP PLEASE HELP ME

Mathematics
2 answers:
mart [117]3 years ago
7 0

Answer: \sum_{n=1}^{5}4^n=1364

Step-by-step explanation:

Since we have given that

\sum_{n=1}^{5}4^n

Now, we know the rule for summation , we'll apply this ,

\sum_{n=1}^{5}4^n\\=4^1+4^2+4^3+4^4+4^5\\

Now, it becomes geometric progression, so we us the formula for sum of terms in g.p. which is given by

S_n=\frac{a(r^n-1)}{r-1}\\\\\text{where 'a' is the first term and 'r' is the common ratio}

So, our equation becomes ,

a=4 \\\\r=\frac{a_2}{a_1}=\frac{4^2}{4}=4\\\\S_5=\frac{4(4^5-1)}{4-1}\\\\S_5=1364

Hence ,

\sum_{n=1}^{5}4^n=1364

UNO [17]3 years ago
5 0

Answer: 1364

<u>Step-by-step explanation:</u>

∑ 4ⁿ   <em>from n = 1 to 5</em>

n = 1:    4¹   =    4

n = 2:   4²   =   16

n = 3:   4³   =   64

n = 4:   4⁴   =  256

n = 5:   4⁵   =<u> 1024 </u>

                     1364


You can also use the formula: S = [a(1 - rⁿ)]/(1 - r)

S = \frac{4(1 - 4^{5})}{1 - 4}

  = \frac{4(1 - 1024)}{-3}

  = \frac{4(-1023)}{-3}

  = \frac{-4092}{-3}

  = 1364

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