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Anuta_ua [19.1K]
3 years ago
14

Simplify the square root of: √32

Mathematics
2 answers:
mylen [45]3 years ago
6 0
The square root of 32 is 5.65685
Wittaler [7]3 years ago
4 0

Answer:

4\sqrt{2}

Step-by-step explanation:

factor the square root of 32

to get a total of 32, you do 4 times 4, which is 16

16 times 2 =32

16 is a perfect square so it's outside of the square root symbol, but you can't find the square root of 2 without it being irrational.

So,

final answer: 4\sqrt{2}

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If log2 5 = a, log2 3 = b and log2 7 = c, determine an expression for log2 (25/21) in terms of a, b, and c
Ilia_Sergeevich [38]

Answer:

2a - b -c

Step-by-step explanation: We know that:

log_{2} 5 = a\\log_{2} 3 = b\\log_2 7 = c\\

and we want:

log_2 \frac{25}{21}.

We can form the numerator using just the first fact (since 5^2 is 25) and the denominator using the latter two (since 3*7 = 21).

log_2 \frac{25}{21} = log_2 \frac{5^2}{3*7}.

The logarithm of a division can be expanded by subtracting the numerator and denominator (while still keeping the log). The logarithm of a product can be expanded by adding the terms while keeping the log. If the logarithm is raised to a power, we can bring it down as a factor:

log_2 \frac{5^2}{3*7} = log_2(5)^2 - log_2 (3*7) = 2 log_2(5) - (log_2 3 + log_2 7)

= 2 log_2(5) - log_2 3 - log_2 7 .

Substituting the variables:

2 log_2(5) - log_2 3 - log_2 7 = 2a - b - c

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