Answer:
an =a1+(n−1)d
Step-by-step explanation:
Answer:

Step-by-step explanation:




Answer:
x=-10
Step-by-step explanation:
6x+4=5x-6
Subtract 5x from each side
6x-5x+4=5x-5x-6
x +4 = -6
subtract 4 from each side
x+4-4 = -6-4
x=-10
(4.5,6) that is what i got.
Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).