<h3>
Answer: 45/121</h3>
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Work Shown:
2 blue, 4 red, 5 green
2+4+5 = 11 total
P(blue) = probability of getting one blue marble
P(blue) = (number of blue)/(number total)
P(blue) = 2/11
A = P(2 blue) = (2/11)*(2/11) = 4/121
P(red) = 4/11
B = P(2 red) = (4/11)*(4/11) = 16/121
P(green) = 5/11
C = P(2 green) = (5/11)*(5/11) = 25/121
Add the values of A,B, and C to get the probability of getting two of the same color
A+B+C = 4/121+16/121+25/121 = 45/121
This is approximately equal to 0.3719 which is roughly a 37.19% chance of happening
Side note: we can add A,B, and C because they are mutually exclusive events.
