Answer: The equation of a straight line is:
y = mx + b
m is the slope, and that is -2.
Hope this helps:/
Answer:
The equation in the standard form of the line through the given points is;
y = 3x - 17
Step-by-step explanation:
We start by getting the slope of the line;
m = (y2-y1)/(x2-x1)
m = (7-10)/(8-9) = -3/-1 = 3
The stands equation form is;
y = mx + b
m is slope, b is the y-intercept
so we have
y = 3x + b
To get b, we substitute the coordinates of any of the points
10 = 3(9) + b
10 = 27 + b
b = 10-27
b = -17
So the equation is;
y = 3x - 17
P= 3
Q= -14
R= -5
Step-by-step explanation:
Just solve the equation on the right side, you'll get:
=3x^2 -15x +x -5
=3x^2 -14x -5
Now compare it to the equation on the left side,
The coefficient of x^2 on the left is "p", on the right that we just solved is 3.
Same for "q" which is the coefficient on the left, on the right it's -14.
And for "r" it's -5 from the equation on the right.
The angle is 162 degrees. Work shown in picture:)
