For this case we have the following inequality:

To find the solution we follow the steps below:
We apply distributive property on the right side of inequality:

Adding 13 to both sides of the inequality we have:

We subtract 6x on both sides of the inequality:

Thus, we have that any value of "x" makes the inequality fulfilled. Thus, the solution is given by all real numbers.
Answer:
The solution set is (-∞,∞)
Y-5=4(x+2)
y-5=4x+8
+5 +5
y=4x+13
is that what you are talking about?
Cosine rule
Cosx=(11 ²+8²-(15²))/2(11)(8)
Cosx=(121+64-225)/176
Cosx=-40/176
Cosx=-5/22
X=cos-1 -5/22
X=103.1
Answer:
60%
Step-by-step explanation:
First, find the total number of sixth graders
To do this, add the number of girls and boys together
girls+boys
There are 60 girls and 90 boys
60+90
150
Now, find the percent of sixth graders that are boys
To do this, divide the number of boys by the total number of sixth graders
boys/total sixth graders (part/whole)
There are 90 boys, and 150 total sixth graders
90/150
0.6
Convert to a percent. Multiply by 100 or move the decimal place two spots to the right
0.6*100=60
0.6-->6.0-->60.
So, 60% are boys
The unknown number is 48 using the equation: x ÷ 12 +49=53 subtract 49 from both sides and get x ÷ 12 = 4 multiplying by 12 on both side to get rid of the ÷12 and get the final answer of x=48.