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Anna71 [15]
3 years ago
10

Help ASAP please! ill mark u brainliest

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0

Answer:

box and whisker

Step-by-step explanation:

You might be interested in
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
Finish the sequence<br> 1,1,2,3,5,8,_,_,_
Papessa [141]
This is a Fibonacci sequence
1; 1
1 + 1 = 2
1 + 2 = 3
2 + 3 = 5
3 + 5 = 8
next terms:
5 + 8= 13
8 +13 = 21
13 + 21 = 34


3 0
3 years ago
Read 2 more answers
Three consecutive integers are n-1, n and n+1. Write an expression for the sum of the three integers.
svlad2 [7]
N-2,n and n+2;n-3,n and n+3,n-4,n and n+4....
6 0
4 years ago
Aki's Bicycle Designs has determined that when x hundred bicycles are​ built, the average cost per bicycle is given by​ C(x)equa
Alenkinab [10]

Answer:

20 Bicycles

Step-by-step explanation:

The function for the average cost,C(x) [in hundred of dollars] per bicycle whenever x hundred bicycles are built is given as:

C(x)=0.5x^2-0.2x+6.756

The minimum value of C occurs at the axis of symmetry.

Axis of Symmetry, x=-\frac{b}{2a}

Comparing with the standard form of a quadratic equation ax^2+bx+c=0

a=0.5, b=-0.2

x=-\frac{(-0.2)}{2*0.5}\\x=0.2

x=0.2 Hundreds =0.2 X 100 =20

When Aki's Bicycle Designs produces 20 Bicycles, the cost is minimized.

5 0
3 years ago
Question 15
Ghella [55]

Answer:

C: -680/9

B: -185/18

7 0
3 years ago
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