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2 years ago

ASAP RIGHT NOW. I AM ON A LIMIT RIGHT NOW. 100 BRAINLEST POINTS WHOEVER ANSWERS FIRST AND GETS IT CORRECT.

Mathematics

1 answer:

horrorfan [7]2 years ago

4 0

Answer:

The answer is $312.00.

Step-by-step explanation:

First you need to find the amount for the groceries and utilities.

The groceries would be $780.00 and the utilities would be $468.00.

Next you have to add them together which would be $1248.00.

Then you have to find the amount for savings.

The Savings would be $936.00.

Lastly you have to subtract $936.00 from $1248.00.

Your final answer will be $312.00.

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June runs a little slower than Carlos. She ran 1/4 of a mile in 3 minutes. How long will it take her to run a full mile?

Lady bird [3.3K]

Alright my friend so if she ran 1/4 a mile in just 3 minutes then her overall time will be 12 minutes because she still has 3 more to go so basically it'll be 3 x 4 = 12

3 0

3 years ago

Read 2 more answers

postnew [5]

12-3=9 they switch up and it still equals the same thing

5 0

2 years ago

Read 2 more answers

Select the expressions that are equivalent to 12n - 8. Select all that apply.

morpeh [17]

A.3n+4+3n+4+4n

=3n+3n+4n+4+4

=10n+8

B.11n+4+n-12

=11n+n+4-12

=12n-8

C.6(6n-2)

=36n-12

D.4(3n-2)

=12n-8

E.4n+22-12+8n

=4n+8n+22-12

=12n+10

so,B and D are the expressions that are equivalent to 12n-8.

3 0

2 years ago

Tienes un triángulo equilátero con lados de 10cm, lo divides en dos partes de manera horizontal tal que el área de ambos figuras

Tanya [424]

Answer:

x = 10/√2 ≈ 7.07

Step-by-step explanation:

Comenzaremos por dividir el triángulo en dos partes y definir H, como en la figura adjunta.

Aplicando el teorema de Tales, sabemos que:

$\dfrac{l/2}{H}=\dfrac{x/2}{h}\\\\\\\dfrac{l}{H}=\dfrac{x}{h}$

También sabemos que, dado que el tirángulo menor es la mitad que el triángulo mayor, la relación entre áreas es:

$\dfrac{A}{A_x}=\dfrac{lH/2}{xh/2}=\dfrac{lH}{xh}=2$

Dado que formamos dos triángulos rectángulos, podemos despejar el valor de H como:

$(l/2)^2+H^2=l^2\\\\H^2=l^2-(l/2)^2=10^2-5^2=100-25=75\\\\H^2=\sqrt{75}$

Podemos entonces despejar x de la siguiente manera:

$h=\dfrac{H}{l}\cdot x=\dfrac{lH}{2x}\\\\\\2x^2\dfrac{H}{l}=lH\\\\\\2x^2=l^2\\\\\\x=\dfrac{l}{\sqrt{2}}=\dfrac{10}{\sqrt{2}}\approx7.07$

6 0

3 years ago

What is the approximate distance between the points (-3,-4)(-8,1) on a coordinate grid?

Alex

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-3}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{-8}~,~\stackrel{y_2}{1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[-8-(-3)]^2+[1-(-4)]^2}\implies d=\sqrt{(-8+3)^2+(1+4)^2} \\\\\\ d=\sqrt{25+25}\implies d=\sqrt{50}\implies d\approx 7.071$

3 0

3 years ago