- 4 - 4 + 4 ÷ 4
- 4 ÷ 4 + 4 ÷ 4
- (4 + 4 + 4) ÷ 4
- √4 + √4 + 4 - 4
- √4 + 4 + 4 ÷ 4
- √4 + 4 + 4 - 4
- 4 + 4 - 4 ÷ 4
- 4 + 4 + 4 - 4
- 4 + 4 + 4 ÷ 4
- √4 + √4 + √4 + 4
- 44/(√4 + √4)
- √4 + √4 + 4 + 4
- 44/4 + 4
- 4 + 4 + 4 + √4
- 44/4 + 4
- 4 * 4 * 4 ÷ 4
- 4 * 4 + 4 ÷ 4
- 4 * 4 - √4 + 4
- 4! - 4 - 4 ÷ 4
- 4 * (4 + 4 ÷ 4)
- 4! - 4 + 4 ÷ 4
- 4 * 4 + 4 + √4
- 4! - √4 + 4/4
- 4 * (√4 + √4 + √4)
- 4! + √2 - 4 ÷ 4
- 4! + √4 + 4 - 4
- 4! + √4 + 4 ÷ 4
- 4! + 4 + 4 - 4
- 4! + 4 + 4 ÷ 4
- 4! + √4 + √4 + √4
Lol, that took a while, hope it helps!
So he would have more landry soap left over
I'm taking "part 3" to mean the 3rd of the posted questions.
If , then
Then when , we get .
18000 represents the price of the new car.
The value of the car in 6 years can be found by substituting 6 for the variable t, as follows:
In 6 years, it will be worth around $8359.27.
The equation for the car worth $20000 is this:
In 6 years, the other car will be worth $7542.99, so the car worth $18000 will have more value in 6 years.
Answer:
Taylor is closest to the table
Step-by-step explanation:
I divided 64, 4, 7, 0.615, and 001 01 and got 1.876 so i figured out that that is half of 64%. So that gave me an idea that Taylor was closest to the table.