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3 years ago

-3 = 3/4r + 2 find r

Mathematics

2 answers:

svetlana [45]3 years ago

8 0

Answer:

-20/3

Step-by-step explanation:

3/4r + 2 = -3

subtract 2 on both sides...

3/4r = -5

divide by 3/4 on both sides...

3/4r divided by 3/4 is r.

-5 divided by 3/4 is the same thing as...

-5 times 4/3 (flip the fraction)

-20/3

Hope this helps!

kow [346]3 years ago

3 0

Answer:

r = -20/3

Step-by-step explanation:

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Choose the graph of the function <br><br>g(x) = 2 x 4^x

dexar [7]

Answer:

its B

Step-by-step explanation:

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8 0

3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

Triangle GHI is rotated 90Degrees clockwise and then reflected over the y-axis. Which congruency statement is true?

lesya [120]

The congruency statement which is true among the answer choices is;

On a coordinate plane, triangle G H I is rotated 90 degrees clockwise and then is reflected over the y-axis.
Triangle G H I is congruent to triangle G double-prime H double-prime I double-prime.

<h3>Which congruency statement is true?</h3>

According to the task content, the initial transformation is; Triangle GHI is rotated 90Degrees clockwise and then reflected over the y-axis.

On this note, the congruency which are true regarding the transformation are;

On a coordinate plane, triangle G H I is rotated 90 degrees clockwise and then is reflected over the y-axis.
Triangle G H I is congruent to triangle G double-prime H double-prime I double-prime.

This follows from the fact that the transformation.does not involved dilation by means of a scale factor and hence, size remains equal and all angle measures remain the same.