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aliina [53]
3 years ago
12

Branliest to correct answer explain how you solved it please

Mathematics
1 answer:
nika2105 [10]3 years ago
4 0

Answer:

{1}

Step-by-step explanation:

A ∩ B ∩ C means A intersection B intersection C. That means the question is asking for a set of numbers that are in sets A, B, and C.

{1} is the answer since it is the only number that is in all three sets.

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G(x)=-3x+2 with a domain of (-1,2) what is the range
BigorU [14]

we are given

g(x)=-3x+2

we can compare it with

slope intercept of line

y=mx+b

so,

slope is m=-3

y-intercept is b=2

Graph:

we can draw graph

Range:

we are given domain

(-1,2]

At x=-1:

g(-1)=-3*-1+2

g(-1)=5

At x=2:

g(2)=-3*2+2

g(2)=-4

we know that

range is all possible values of y

so, range is

[-4,5).........Answer

7 0
3 years ago
What 1/2 as a decimal??? plaese helppp
DaniilM [7]

Answer:

Its 0.50 I hope i helped


7 0
4 years ago
In a bag, there are only black pins, green pins, pink pins and white pins
kozerog [31]

Answer:

P of white: 0.26

P of green: 0.39

Step-by-step explanation:

Assume the probability of a white pin is p.

Then the probability of a green pin is (3/2)p because their ratio is 3:2.

The sum of the probabilities must be 1.

0.1+(3/2)p+0.25+p=1

(5/2)p+0.35=1

(5/2)p=0.65

p=(2/5)(0.65)=0.26

(3/2)p=0.39

6 0
3 years ago
In the figure to the right, if AC = 15 and BC = 12, what is the radius?
Andrew [12]

Answer:

The radius is 9.0 units

Step-by-step explanation:

we know that

In the right triangle of the figure ABC

Applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

15^2=AB^2+12^2

solve for AB

AB^2=15^2-12^2\\AB^2=81\\AB=9\ units

Remember the the side AB of right triangle represent the radius of the circle

therefore

The radius is 9.0 units

6 0
3 years ago
A rectangular park is 100 yards long and 65 yards wide. Give the length and width of another rectangular park that has the same
Akimi4 [234]
100 by 65 = 330 perimeter = 6,500 area
90 by 75 = 330 perimeter = 6,750 area


5 0
4 years ago
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