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2 years ago

What is the rectangular form of 17(cos(315°) + isin(315°))?

Mathematics

2 answers:

Arlecino [84]2 years ago

7 0

Answer:

Step-by-step explanation:

EDG2021

Dmitriy789 [7]2 years ago

5 0

Answer:

it is answer A. I did the test bro :)

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You work as a quality control inspector of shirts for a clothing manufacturing company. Today you examine one batch and 15% fail

Otrada [13]

Answer:

23%

Step-by-step explanation:

To find how many failed inspection, add together all the percentages:

15 + 5 + 3

= 23

So, 23% of the products failed inspection

5 0

2 years ago

The sum of 27 and a number n

Jobisdone [24]

Answer:

Its X And The Sum Of N Is Going To Be 27

4 0

2 years ago

At the "cloth for you" shop, you can buy a top for £10.00 and a Bermuda trouser for £12.00. Due to a sensational sell, there is

9966 [12]

Answer:

£32 in total for the top and two trousers

Step-by-step explanation:

The price for a top In the "cloth for you" shop= £10

The price for a bermuda trouser In the "cloth for you" shop= £12

There is a 20% discount on tops

The price If I bought one top and would trouser will be

(10-(0.2*10)) for the top

2(12) for the trouser

Total= (10-(0.2*10))+ 2(12)

Total = 10-2+24

Total = £32

So I spent £32 in total for the top and two trousers

3 0

3 years ago

Javier simplified the expression below. Find and describe the three mistakes he made.

OverLord2011 [107]

$( \dfrac{20x}{5x^8})^-^3$

<span>Take out the constants
</span>
$( \dfrac{20}{5} * \dfrac{x}{x^8} ) ^-^3$

$(4*\dfrac{x}{x^8} ) ^-^3$

Use the rule : $\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}
$

$(4x^1^-^8)^-^3$

$(4x^-^7)^-^3$

Use the n<span>egative power rule : </span> ${x}^{-a}=\frac{1}{{x}^{a}}
$

$\frac{1}{4(x^-^7)}^-^3$

$\frac{1}{4^3(x^-^7)}^-^3$

$\dfrac{1}{64x^-^2^1}$

$\dfrac{1}{64* \dfrac{1}{x^2^1}}$

$\dfrac{1}{64 \dfrac{}{x^2^1}}$

$= \dfrac{x^2^1}{64}$

6 0

2 years ago

Read 2 more answers

Pls help only b,d, and f

Leya [2.2K]

Solving for y right?

2y = 3x + 4 - x
2y = 2x + 4
y = 2x + 4 over 2
y = 2 (x + 2) over 2
y = x + 2

y - 3 = 2x - 6 over 2
y - 3 = 2(x - 3) over 2
y - 3 = x - 3
y = x

x - y - 2 = 2(2x + 1)
-y - 2 = 2(2x + 1) - x
-y = 2(2x + 1) - x + 2
y = -2(2x + 1) + x - 2

8 0

2 years ago