Answer:
5.81%
Step-by-step explanation:
Answer:
log 2 + 3 logx
Step-by-step explanation:
log 2x^3
log2+logx^3
log^2+3logx
![\left( \dfrac 1 {64} \right)^{- 5/6} =64^{5/6} = (\sqrt[6]{64})^5 = 2^5 =32](https://tex.z-dn.net/?f=%20%5Cleft%28%20%5Cdfrac%201%20%7B64%7D%20%5Cright%29%5E%7B-%205%2F6%7D%20%3D64%5E%7B5%2F6%7D%20%3D%20%28%5Csqrt%5B6%5D%7B64%7D%29%5E5%20%3D%202%5E5%20%3D32)
TRUE
![\sqrt[5]{36^4}=36^{4/5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B36%5E4%7D%3D36%5E%7B4%2F5%7D)
which surely isn't 36. FALSE

FALSE
For the fourth one we have a

which isnt

so this is FALSE.





No fractions in that one so FALSE.
Answer:
-19
Step-by-step explanation:
4x-8(2-x)
4x-16+8x
12x-16
12(-1/4)-16
-12/4-16
-3-16
-19