4x-9/y+11=0,6/y-3x=8
1 answer:
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Answer:
Step-by-step explanation:
The mean (or average) of a set of numbers can be found with the following formula:
For this problem, we have five numbers, so we add them together and divide by 5:
No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
or 
so
if w^2-9w+81 is perfect square, factored form is either
or 
aka 
or 
expand them
(x+9)^2=x^2+18x+81, wron middle term
(x-9)^2=x^2-18x+81 wrong
so it is not
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
so
if w^2-9w+81 is perfect square, factored form is either
expand them
(x+9)^2=x^2+18x+81, wron middle term
(x-9)^2=x^2-18x+81 wrong
so it is not