Answer:
0.35% of students from this school earn scores that satisfy the admission requirement.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.
This means that 
The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?
The proportion is 1 subtracted by the pvalue of Z when X = 2294. So



has a pvalue of 0.9965
1 - 0.9965 = 0.0035
0.0035*100% = 0.35%
0.35% of students from this school earn scores that satisfy the admission requirement.
I think that this is the resolution
2/3×5/-4 = 10/-12
hope this helps
Answer:
Mean
Step-by-step explanation:
Since 360 is such a greater amount of time than the previous ones, it will greatly affect the mean.
f(x) = 57 (19)^(x-4)
The domain is the input or x values
what are the allowed x values
we can put in any values of x we want and the function still works
Domain: all real values
The range is the output or the y values
It will always be greater than 0
Range: y> 0 or all positive real numbers
4x - 13 = 2x + 9
Add 13 to each side
4x = 2x + 22
Subtract 2x from both sides
2x = 22
Divide both sides by 2
x = 11