Solve the inequality. graph your solution 6(y+1)>6
1 answer:
You might be interested in
Answer:
Second : 1/6 x + 47
Third : 1 2/3 x + 35 - 1 1/2 x + 12
Fourth : 5 (1/3x) + (5) (7) - (3) (1/2x) + (3) (4)
Step-by-step explanation:
I would start by expanding the expression, showing each step. Then, simplify by collecting like terms.
To expand, you multiply the term outside of the brackets by each term inside the brackets.
5(1/3x + 7) - 3(1/2x - 4)
= 5(1/3x) + (5)(7) - (3)(1/2x) + (3)(4) Showing how to expand
= 5/3x + 35 - 3/2x + 12 Simplified above step by multiplying
= 5/3x - 3/2x + 47 Collected like terms (35 + 12 = 47)
= 10/6x - 9/6x + 47 Change fractions to the common denominator 6
= + 47 Combine fractions with common denominator
= 1/6x + 47 Fully expanded
See which options match the steps I took to expand the original expression.
The second step is the same as option 4.
The last step is the same as option 2.
I bolded those steps that are the same.
Some options use mixed fractions (whole numbers and fractions).
From the third step, I will convert the improper fractions to mixed fractions.
5/3x + 35 - 3/2x + 12
= 1 2/3x + 35 - 1 1/2x + 12
This is the same as option 3.
On the left side, 5 goes into 3 ONE time. The ONE becomes the whole number. After 5 goes into 3, there is 2 left, which becomes the numerator.
On the left side, 3 goes into 2 ONE time. The ONE becomes the whole number. The remainder is 1, which becomes the numerator.
Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm
we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=
0=x^2+12x+16
a=1
b=12
c=16
x=
x=
x=
x=
x=
x=
or 
aprox
x=-1.52786 or -10.4721
those are the numbers
the numbes are -1.52786 or -10.4721
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm
we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=
0=x^2+12x+16
a=1
b=12
c=16
x=
x=
x=
x=
x=
x=
aprox
x=-1.52786 or -10.4721
those are the numbers
the numbes are -1.52786 or -10.4721