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iren [92.7K]
3 years ago
10

After winning a soccer game, the coach took the team out for ice cream cones. He spent $21 on 12 single-scoop ice cream cones. I

f all the ice cream cones cost the same amount, what was the cost of one ice cream cone?
Mathematics
1 answer:
Alborosie3 years ago
6 0

Answer:

Unitary cost= $1.75

Step-by-step explanation:

Giving the following information:

He spent $21 on 12 single-scoop ice cream cones.

<u>To calculate the unitary cost, we need to use the following formula:</u>

Total cost= number of units*unitary cost

Unitary cost= total cost / number of units

Unitary cost= 21 / 12

Unitary cost= $1.75

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ioda
It’s 2/3. 16/24 would be divided by 2 and would be changed into 8/12. Divide it by 2 again, and you’ll get 4/6. Then divide again, 2/3.
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Which is true about the completely simplified difference of the polynomials a3b + 9a2b2 − 4ab5 and a3b − 3a2b2 + ab5?
Mrrafil [7]

Answer:

The difference is a binomial with a degree of 6

Step-by-step explanation:

Given:

a^3b + 9a^2b^2 − 4ab^5 and a^3b − 3a^2b^2 + ab^5

Let A = a^3b + 9a^2b^2 - 4ab^5

B= a^3b - 3a^2b^2+ab^5

The difference between A and B is

A - B = a^3b + 9a^2b^2 - 4ab^5 - (a^3b - 3a^2b^2 + ab^5)

Open parenthesis

A - B= a^3b + 9a^2b^2 - 4ab^5 - a^3b + 3a^2b^2 - ab^5

= a^3b - a^3b + 9a^2b^2 + 3a^2b^2 - 4ab^5 - ab^5

= 12a^2b^2 - 5ab^5

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The second term 5ab^5 has 1 +5 =6 as a degree

Therefore,

the answer is: The difference is a binomial with a degree of 6

3 0
3 years ago
Calculate the number of subsets and the number of proper subsets for the set.
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A set of n elements has 2ⁿ subsets. One of these subsets is the set itself, so this set would have 2ⁿ - 1 <em>proper</em> subsets.

The given set has 4 elements, so it has 2⁴ = 16 subsets and 2⁴ - 1 = 15 proper subsets.

Just to illustrate the claim, we have

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{ } (empty set)

• subsets of size 1 (4 of these):

{1/6}, {1/7}, {1/8}, {1/9}

• subsets of size 2 (6 of these):

{1/6, 1/7}, {1/6, 1/8}, {1/6, 1/9}, {1/7, 1/8}, {1/7, 1/9}, {1/8, 1/9}

• subsets of size 3 (4 of these):

{1/6, 1/7, 1/8}, {1/6, 1/7, 1/9}, {1/6, 1/8, 1/9}, {1/7, 1/8, 1/9}

• subsets of size 4 (1 of these):

{1/6, 1/7, 1/8, 1/9}

and the last one is the only subset that is not a proper subset, because that subset = the set.

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2 years ago
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