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RideAnS [48]
2 years ago
9

Please help- will give brainlist

Mathematics
1 answer:
marshall27 [118]2 years ago
7 0

Answer:

m(JCA)

Step-by-step explanation:

C is the central angle here (the one in between)

so it will be m(JCA) or m(ACJ)

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The math teachers had a party over the weekend where they all had some of
Irina-Kira [14]

Answer:

7 1/3 bowls

Step-by-step explanation:

5 1/2 divided by 3/4=7 1/3

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3 years ago
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A glass plummet weighs 14.35 g in air 5 points 11.40 g when immersed in water, and 8.95 g when immersed in sulfuric acid. Calcul
elena-s [515]

Answer:

0.865

Step-by-step explanation:

Specific gravity is a ratio of the weight of a substance to the weight of an equal volume of a substance chosen as a standard. The standard for liquid and solids is water while for gas is hydrogen.

Amount of displaced oil = 12.64 g — 9.12 g = 3.52 g

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2 years ago
Is 3x-5+y=2y-4 linear if so write the equation in standard form and give the values of A B and C
ruslelena [56]
Equation in standard form:
Ax+By=C

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3x-5+y=2y-4
3x+y-2y=-4+5
3x-y=1

Therefore:
A=3
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C=1

Answer: the equation in standard form would be: 3x-y=1; and the values of A, B and C would be: A=3; B=-1 and C=1.
8 0
3 years ago
How do you do it? What do you take away and do after?
Nuetrik [128]

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5 0
2 years ago
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There are 5 pens in a container on your desk. Among them, 3 will write well but 2 have defective ink cartridges. You will select
Norma-Jean [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Total Number of pens = 5

Number of defective pens = 2

Number of non-defective pens = 3

A.) number of defective pens selected :

X : {0, 1, 2}

It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.

2.)

Defective as Success (since selecting a defective pen is the point of interest.

3.)

Since selection is done without replacement

Probability of success per selection is different for each selection ;

Number of defective = 2

Number of observations = 5

P(success on first selection) = 2/5

P(success on second selection) = 1/4

Hence, X is not well approximated by a binomial random variable.

4.) if selection is done with replacement ; then then the probability of success per selection will be the Same for each selection made. Hence, X will be well approximated by a binomial Random variable.

5.) If sampling is done without replacement, then the the hypergeometric function will be a more effective approximation.

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