Answer:
x=13 degrees
Step-by-step explanation:
First, think of the remote interior angle theorem. So basically the remote interior angles that don't share a vertex with the exterior angle is the sum of the exterior angle. So that means ∠EBC+∠BEC=∠ECD. ∠ECD=64 degrees+90 degrees=154 degrees. ∠EBC is equal to 180 degrees minus 3x because line AD is a line so ∠ABE and ∠EBC are supplementary angles so basically they add up to 180 degrees. So the equation is (180-3x)+x=154. Simplify the equation and you should get x=13 degrees:)
Answer: 2(x^2-2x+4)
Step-by-step explanation:
You can factour out 2:
2(x^2-2x+4)
I'm not sure your question has enough information to be answered properly, but I'll try to help:
Assuming each of them are sweeping 1/2 of the garge, we're gonna cut each of their times in half.
Now the girl needs 10 minutes for half the garage and her brother needs 15 minutes.
So, if they work together, the first ten minutes will overlap each other while the girls brother gets left behind to finish up for an extra five minutes.
So, when working together, the boy and the girl need 15 minutes to sweep the garage.
Answer: A
Step-by-step explanation:
The first square is 22 inches on a side.
The second is 17.6 inches on a side
the third is 14.08 inches on a side.
We can suppose that we have a constant rate of decrease betwen the sides cubes, this means that:
22in*x = 17.6in
where x is the rate of scale.
x = 17.6/22 = 0.8
Now we test this with the second and third:
17.6in*0.8 = 14.08in
Ok, this works.
then the side of n-th cube can be found with the equation
L = 22*0.8^(n-1)
we can try the different options and see which one gives a value smaller than 10.
A) n = 5
L = 22*0.8^4 = 9.01
Then the correct option is A
Answer:
Aluno X
Step-by-step explanation:
A nota média para os alunos X e Y são, respectivamente:
A variância é definida pela seguinte expressão:
Onde n é o numero de termos, neste caso, n = 4.
As variâncias para cada aluno são:
O aluno X apresentou uma variância menor do que o aluno Y em suas notas e, portanto, apresentou ser o mais regular.
