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frosja888 [35]
3 years ago
15

Find the length of the rectangle whose area is 99 square inches and the width is 9 inches.

Mathematics
1 answer:
Oliga [24]3 years ago
7 0

Answer:

the answer is 11

Step-by-step explanation:

??×9=99

9÷99=11

11×9=99

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Step-by-step explanation:

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4y=5x-1

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Write the next three numbers in each counting sequence:<br> ...,40, 30, 20, ____, ____, ____,...
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dimulka [17.4K]

Answer:

x = 9

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Step-by-step explanation:

Side-Side-Side or SSS means that if all three sides of one triangle are equal to all three corresponding sides of another triangle, then the two triangles are considered to be congruent (equal).

Therefore, GH = PM  ⇒  7x + 8 = 6y - 7

and,            GP = HM  ⇒  8x - 10 = 5y - 3

Rewrite the first expression to make x the subject, then substitute this into the second equation, and solve for y:

         GH = PM  

⇒  7x + 8 = 6y - 7

⇒        7x = 6y - 15

⇒           x = (6/7)y - 15/7

Substituting  x = (6/7)y - 15/7  into GP = HM:

                              GP = HM  

⇒                      8x - 10 = 5y - 3

⇒  8[(6/7)y - 15/7] - 10 = 5y - 3

⇒  (48/7)y - 120/7 - 10 = 5y - 3

⇒                      (13/7)y = 169/7

⇒                               y = 13

Now we have found a value for y, substitute this into one of the expressions and solve for x:

    8x - 10 = 5y - 3

⇒  8x - 10 = (5 x 13) - 3

⇒  8x - 10 = 62

⇒          8x = 72

⇒            x = 9

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2 years ago
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