3 years ago

Find the length of the rectangle whose area is 99 square inches and the width is 9 inches.

Mathematics

1 answer:

Oliga [24]3 years ago

7 0

Answer:

the answer is 11

Step-by-step explanation:

??×9=99

9÷99=11

11×9=99

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3/5 to second power times 25

Anestetic [448]

The answer is 9 because 3/5 to second power is 9/25 then you multiply it by 25 and you get 9

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2 years ago

Evaluate the function. f(x) = x² - 4x – 12 Find f(-7)

pashok25 [27]

Answer:

Your answer is 65

Step-by-step explanation:

f(x) = x² - 4x - 12

f(-7) = (-7)² - 4 x (-7) - 12

= 49 - (-28) - 12

= 49 + 28 - 12

= 77 - 12

= 65

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1 year ago

Complete the paragraph proof.

lions [1.4K]

Answer:

wea did tha r come from??

Step-by-step explanation:

it is supposed to be d

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2 years ago

Irene is cutting construction paper into rectangles for a project. She needs to cut one rectangle that is 8 inches × 13 1/2 inch

Rus_ich [418]

Answer:

# weeks ago

Step-by-step explanation:

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2 years ago

For the following pair of functions, find (f+g)(x) and (f-g)(x).

ch4aika [34]

Given:

The functions are

$f(x)=4x^2+7x-5$

$g(x)=-9x^2+4x-13$

To find:

The functions $(f+g)(x)$ and $(f-g)(x)$ .

Solution:

We know that,

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=4x^2+7x-5-9x^2+4x-13$

$(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)$

$(f+g)(x)=-5x^2+11x-18$

And,

$(f-g)(x)=f(x)-g(x)$

$(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)$

$(f+g)(x)=4x^2+7x-5+9x^2-4x+13$

$(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)$

$(f-g)(x)=13x^2+3x+8$

Therefore, the required functions are $(f+g)(x)=-5x^2+11x-18$

and $(f-g)(x)=13x^2+3x+8$ .

7 0

2 years ago