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Alik [6]
3 years ago
5

Please help me with this it’s due today

Biology
1 answer:
uranmaximum [27]3 years ago
3 0

Answer:

The correct answer is - 0 m/s.

Explanation:

In this position-time graph or distance-time graph, there are three different part that shows three different velocities one in increasing as it moves from a lower position in relative to time and one is stationary and the third is decreasing.

'Straight lines' on a distance-time graph suggest that the movement of the object is constant. During 'Part B' of the journey the object travels 0m in 3s. It is stationary for 3 seconds so the velocity will be zero as well.

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The ATP yield for a molecule depends on where it enters glycolysis or the citric acid cycle. The yield can be compared to the ne
Andru [333]

Answer:

a) The net ATP yield from fructose 1,6‑bisphosphate is 32 ATP

b) The net ATP yield from galactose is 30 ATP

c) The net ATP yield from dihydroxyacetone phosphate is 16 ATP

d) The net ATP yield from pyruvate is 12.5 ATP

e) The net ATP yield from lactate is 14 ATP

f) The net ATP yield from phosphoenolpyruvate is 13.5 ATP

Explanation:

a) In this case, 2 ATP molecules are not used for the phosphorylation of glucose for the production of fructose bisphosphate 1.6, thus, the net ATP yield is 32 ATP.

b) Galactose is converted to glucose-1-phosphate through reactions that lead to phosphorylation. Glucose-1-phosphate is transformed into glucose-6-phosphate by the enzyme phosphoglucomutase. Later it is used in glycolysis, thus, the net ATP yield is 30 ATP.

c) The fructose 1,6 bisphosphate is decomposed in glyceraldehyde-3-phosphate and dihydroxyacetone phosphate. Dihydroxyacetone phosphate is isomerized to glyceraldehyde -3-phosphate. ATP performance is (2.5+2.5+11) = 16 ATP

d) Pyruvate is decarboxylated oxidatively to produce acetyl-CoA. ATP yields are:

Glycolysis = 0

Oxidative decarboxylation = 2.5 ATP

TCA cycle = 10 ATP

The net yield is 2.5 + 10 = 12.5 ATP

e) Lactate is oxidized to pyruvate by the enzyme lactate dehydrogenase with a reduction of NAD. Pyruvate is brought into the mitochondria, where it is decarboxylated oxidatively to produce acetyl-CoA. If 1.5 ATP is assumed for cytosolic NADH, therefore 1.5 is produced. So, the net yield is: 12.5 + 1.5 = 14

f) Phosphoenolpyruvate is converted to pyruvate by ATP production through phosphorylation. ATP yield is as follows:

Glycolysis = 1

Oxidative decarboxylation = 2.5 ATP

TCA cycle = 10 ATP

The net yield is 1 + 2.5 + 10 = 13.5 ATP

6 0
3 years ago
What name is given to elements with the same number of protons but differing numbers of neutrons? ions acids isotopes bases
Sphinxa [80]
Isotopes


The answer has to be 20 characters long so this is irrelevant.
8 0
3 years ago
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According to the graph, what condition is best for enzyme
SOVA2 [1]

Answer:

B: A temperature of 35°C

6 0
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How would a scientist have made the distinction between a unicellular and a multicellular organism in the 17th century(1600s), t
Drupady [299]

Using a microscope

Explanation:

A microscope is a scientific device used for magnifying and studying very tiny features.

It was invented by Anton Von Leeuwenhoek in the 17th century.

  • A unicellular organism is an organism made up of a single cell.
  • A multi-cellular organism is made up of several cells.
  • A cell is a very small microscopic structure.
  • It is usually described as the fundamental unit of life.
  • Due to its small size, the naked eyes cannot see it
  • The invention of the microscope opened up the world of cells.
  • Since they have been around for a long time, distinction of cells would have been made possible at those times using a microscope.

learn more:

Microscope brainly.com/question/4065308

#learnwithBrainly

5 0
3 years ago
Large molecules such as glucose move across cell membranes through special protein channels during?
Pavel [41]

Answer:

Glucose is a six-carbon sugar that is directly metabolized by cells to provide energy. ... A glucose molecule is too large to pass through a cell membrane via simple diffusion. Instead, cells assist glucose diffusion through facilitated diffusion and two types of active transport.

Explanation:

4 0
3 years ago
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