Since you use your dominant more it leads to motorrecruitment and larger muscle fibers
Answer: A . Has its collagen fibers randomly orientated.
Explanation:
In the microscopic anatomy of the bone, an osteon (basic microscope unit of the bone) can be arranged into two categories; woven bone or lamellar bone.
As the name suggests woven bone is characterized by the random orientation of the collagen fibers . These collagen fibers haphazardly form to give the visual appearance of an intertwined (woven) network of collagen fibers.
Due to the randomness of the collagen fibers orientation woven bone is thus mechanically weaker than lamellar bone. Woven bone is formed/produced when osteoblasts produce osteoids rapidly within the bone matrix thus woven bone has the ability to form quickly as needed.
Woven bone is thus immature bone or pathologic bone with no stress orientation, it has a high percentage of osteocytes per unit volume and a high rate of turnover.
The macula densa cells monitor the NaCl content of the filtrate entering the distal convoluted tubule.
Define juxtaglomerular apparatus.
The juxtaglomerular apparatus, often referred to as the juxtaglomerular complex, is a kidney structure that controls how each nephron, or functional unit of the kidney, performs.
What are macula densa cells ?
According to the traditional paradigm, the distal nephron's macula densa cells serve as salt sensors and send chemical signals to the juxtaglomerular apparatus to regulate key kidney activities like renal blood flow, glomerular filtration, and renin release.
Learn more about macula densa cells here:-
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Answer:
Although both algae and plants are photosynthetic in nature and are classified as eukaryotes (have highly differentiated cells that contain specialized structures like the nucleus), the two still differ in the following aspects: Algae can either be unicellular and multi- cellular while plants are multi-cellular
The repeats which occur together on a chromosome are referred to as VNTR. The length of each repeat is 60bp.
The first primer is 20bp and is 53 bp away from 1st repeat. Therefore, the total length of sequence amplified by the first primer till 1st repeat = 20+53 = 73bp. Beyond this point 6 repeats on 60 bp are present, hence, the length becomes = 73 + (60X6) = 433bp.
Now the reverse primer which is 21bp in length is located 28bp from the repeat on its side. Reverse primer comes from the opposite direction, so it must be present after the 6 repeats.
The total length of the amplified region = 433 + 28 + 21 = 482 bp.
