Well,
If the slope of the lines are the same, then the lines are parralel.
We need to manipulate 2y - 10x = 4 into y = mx + b form.
Add 10x to both sides
2y = 10x + 4
Divide both sides by 2
y = 5x + 2
Do the same thing with the other equation.
Add 2 to both sides
y = 5x + 2
y = 5x + 2
It appears that, not only are they parallel, but they lie on exactly the same line! If this was a System of Simultaneous Linear Equations, then there would be an infinite number of solutions!<span />
Answer:

Step-by-step explanation:
we know that
The <u><em>conjugate root theorem</em></u> states that if the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial
In this problem we have that
The polynomial has roots 1 and (1+i)
so
by the conjugate root theorem
(1-i) is also a root of the polynomial
therefore
The lowest degree of the polynomial is 3
so

Remember that
The leading coefficient is 1
so
a=1
![f(x)=(x-1)(x-(1+i))(x-(1-i))\\\\f(x)=(x-1)[x^{2} -(1-i)x-(1+i)x+(1-i^2)]\\\\f(x)=(x-1)[x^{2} -x+xi-x-xi+2]\\\\f(x)=(x-1)[x^{2} -2x+2]\\\\f(x)=x^{3}-2x^{2} +2x-x^{2} +2x-2\\\\f(x)=x^{3}-3x^{2} +4x-2](https://tex.z-dn.net/?f=f%28x%29%3D%28x-1%29%28x-%281%2Bi%29%29%28x-%281-i%29%29%5C%5C%5C%5Cf%28x%29%3D%28x-1%29%5Bx%5E%7B2%7D%20-%281-i%29x-%281%2Bi%29x%2B%281-i%5E2%29%5D%5C%5C%5C%5Cf%28x%29%3D%28x-1%29%5Bx%5E%7B2%7D%20-x%2Bxi-x-xi%2B2%5D%5C%5C%5C%5Cf%28x%29%3D%28x-1%29%5Bx%5E%7B2%7D%20-2x%2B2%5D%5C%5C%5C%5Cf%28x%29%3Dx%5E%7B3%7D-2x%5E%7B2%7D%20%2B2x-x%5E%7B2%7D%20%2B2x-2%5C%5C%5C%5Cf%28x%29%3Dx%5E%7B3%7D-3x%5E%7B2%7D%20%2B4x-2)
X= -4 So just put that I’m pretty sure it that if not I’m soooo sorry
Answer:
C→CO2 + 4e
⁻
O2 + 4e⁻ + CO2
Step-by-step explanation:
Answer:
square root?
Step-by-step explanation: