A shape is being designed such that it is a combination of an isosceles triangle with a semicircle whose diameter is the base of
the triangle. The isosceles triangle has legs that are 10 inches and a vertex angle that measures 40 degrees Determine the area of the semicircle to the nearest tenth
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<u>Let's solve this problem step-by-step</u>
<u>Let's set</u>:
2x + 6y = 36 -- equation 1
x + 4y = 20 -- equation 2
(equation 2) * 2
2x + 8y = 40 -- equation 3
(equation 3) - (equation 1)
2y = 4
y = 2 -- equation 4
Plug (equation 4)'s value of y into (equation 2)
x + 4(2) = 20
x = 20 - 8
x = 12
<u>Thus x = 12 and y = 2</u>
<u>Let's check, by substituting these values</u>
<u>Answer: x = 12 and y = 2</u>
Hope that helps!
Answer: The area of the triangle is 24 square inches
Step-by-step explanation:
Hi, since the 2 triangles form a parallelogram ( see attachment) we have the base and height of the triangles, we have to apply the next formula:
Area of a triangle; (base x height) /2
Replacing with the values:
A = (8x6 )/2
A = 48 /2
A = 24 square inches
The area of the triangle is 24 inches
Feel free to ask for more if needed or if you did not understand something.
SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
The details of the solution are as follows:
What variable expression should you subtract from both sides of the equation so that you are left with no variables on the right-hand side?
The variable expression is: subtract 5x from both sides so that you are left with no variables on the right-hand side
CONCLUSION:
The final answer is:
