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Stels [109]
2 years ago
5

A shape is being designed such that it is a combination of an isosceles triangle with a semicircle whose diameter is the base of

the triangle. The isosceles triangle has legs that are 10 inches and a vertex angle that measures 40 degrees Determine the area of the semicircle to the nearest tenth
No links.

Mathematics
1 answer:
Alla [95]2 years ago
6 0

Answer: Find the base than add

Step-by-step explanation:

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Answer:

203

Step-by-step explanation:

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How to get answer for number 1: | 4+2i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}

How to get answer for number 2: | 5-i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}

Number 3 how to get answer: | -3i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3

4 0
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I need help pls, youl get a lot of points
lora16 [44]

Answer:

1st, 3rd and 4th

Step-by-step explanation:

Only 2nd is false

6 0
3 years ago
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frosja888 [35]
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