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alexandr1967 [171]
3 years ago
10

There are 24 different tables to set up for field day.The principal wants the tables set up in equal rows.should she use 3 rows

or 5 rows?Explain
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
8 0
There should be 3 rows because 24 divided by 3 equals 8.
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What is the surface area of this rectangular prism?<br><br> 5 ft<br> 4 ft<br> 12 ft
givi [52]

Answer:

256 ft²

Step-by-step explanation:

SA=2(lw+lh+wh) where l is length and w is width and h is height

Plug in the given information

SA=2(5*4+5*12+4*12)\\SA=2(20+60+48)\\SA=2(80+48)\\SA=2(128)\\SA=2(128)\\SA=256

Therefore, the surface area of the rectangular prism is 256 ft².

I hope this helps!

5 0
3 years ago
Read 2 more answers
If Joe earns $25 per hour during a normal week (40 hours per week), but earns $37.50 per overtime, how much does he earn in 48 h
Svetradugi [14.3K]

Answer:

1300

Step-by-step explanation:

Regular time is 40 hours at 25 dollars per hour

Regular pay is 40*25 = 1000

He worked 48 hours, 48-40 =8, so he worked 8 hours overtime

8 hours at 37.50 overtime pay

8*37.50=300

His total pay is regular pay plus overtime pay

1000+300 = 1300

4 0
4 years ago
Hank has a bottle of diluted syrup that is 60% maple syrup and a bottle of pure syrup that is 100% maple syrup in his restaurant
Nezavi [6.7K]

9514 1404 393

Answer:

  62.5 oz of 100%

Step-by-step explanation:

Let p represent the number of ounces of pure syrup. Then (100-p) is the number of ounces of 60% syrup. The amount of maple syrup in the desired mix is ...

  p +0.60(100 -p) = 0.85(100)

  0.40p +60 = 85 . . . . . . . . . . . simplify

  0.40p = 25 . . . . . . . . . . subtract 60

  p = 62.5 . . . . . . . . . divide by 0.4

62.5 ounces of pure syrup should be mixed with the diluted syrup to make 100 ounces of 85% maple syrup.

_____

The other 37.5 ounces will be 60% syrup.

3 0
3 years ago
I NEED HELP ASAP tryna gets a goods grade ons me test TY Ly muffin
Aleks04 [339]

142 meters

with all the mathy stuff i did the answer was 142 meters

5 0
3 years ago
A​ true/false test has 8080 questions. Suppose a passing grade is 5252 or more correct answers. Test the claim that a student kn
Makovka662 [10]
<h2>Answer with explanation:</h2>

Let p be the proportion of the correct answers.

As per given , we have

H_0: p=0.50

H_a: p>0.50 , since the alternative hypothesis is right tailed , so the test is a one -tailed test.

If the student gets 52 answers correct out of 80.

i.e. the proportion of correct answers : \dfrac{52}{80}=0.65

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.65-0.50}{\sqrt{\dfrac{0.50(0.50)}{80}}}\approx2.68

P-value : P(z>2.68)=0.0037   [ by using p-value table for z (right-tailed)]

Since the p-value(0.0037) is less than the significance level (0.05), so we reject the null hypothesis.

Results : We have enough evidence to support the claim that a student knows more than half of the answers and is not just guessing.

8 0
4 years ago
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