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alexandr1967 [171]

3 years ago

10

There are 24 different tables to set up for field day.The principal wants the tables set up in equal rows.should she use 3 rows

or 5 rows?Explain

1 answer:

Ira Lisetskai [31]3 years ago

8 0

There should be 3 rows because 24 divided by 3 equals 8.

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How do i solve this

laila [671]

The ratio is 2:3 for the side lengths of the triangles.

so 6:9 is one side and 5:x would be the other side

2/3 of five is 3.33 and multiplying that by 2 gives you 6.67

4 0

3 years ago

What is the solution to 5a-15+9a=3a+29

pogonyaev

5a-15+9a=3a+29

We simplify the equation to the form, which is simple to understand

5a-15+9a=3a+29

We move all terms containing a to the left and all other terms to the right.

+5a+9a-3a=+29+15

We simplify left and right side of the equation.

+11a=+44

We divide both sides of the equation by 11 to get a.

a=4

3 0

3 years ago

Read 2 more answers

if there are 2040 seats in a section of a stadium, 20 seats in the first row, and 4 more seats in each row, how many rows are th

Lorico [155]

2040 = n/2(20+(n-1)4)

4080 = n(20+4n-4)

4080= 20n +4n^2 -4n

1020 = 4n + n^2

n^2 +4n -1020 =0

use common formula (can't write out so just look at answers. sorry)

which gives answers of n=-34 and n=30. since n can only be positive, n=30 so there are 30 rows. I liked that challenge

5 0

3 years ago

Read 2 more answers

With a height of 68 in, Nelson was the shortest president of a particular club in the past century. The club presidents of the

Ivahew [28]

Answer:

a. The positive difference between Nelson's height and the population mean is: $\\ \lvert 68-70.7 \rvert = \lvert 70.7-68 \rvert\;in = 2.7\;in$ .

b. The difference found in part (a) is 1.174 standard deviations from the mean (without taking into account if the height is above or below the mean).

c. Nelson's z-score: $\\ z = -1.1739 \approx -1.174$ (Nelson's height is <em>below</em> the population's mean 1.174 standard deviations units).

d. Nelson's height is <em>usual</em> since $\\ -2 < -1.174 < 2$ .

Step-by-step explanation:

The key concept to answer this question is the z-score. A <em>z-score</em> "tells us" the distance from the population's mean of a raw score in <em>standard deviation</em> units. A <em>positive value</em> for a z-score indicates that the raw score is <em>above</em> the population mean, whereas a <em>negative value</em> tells us that the raw score is <em>below</em> the population mean. The formula to obtain this <em>z-score</em> is as follows:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

Where

$\\ z$ is the <em>z-score</em>.

$\\ \mu$ is the <em>population mean</em>.

$\\ \sigma$ is the <em>population standard deviation</em>.

From the question, we have that:

Nelson's height is 68 in. In this case, the raw score is 68 in $\\ x = 68$ in.
$\\ \mu = 70.7$ in.
$\\ \sigma = 2.3$ in.

With all this information, we are ready to answer the next questions:

a. What is the positive difference between Nelson's height and the mean?

The positive difference between Nelson's height and the population mean is (taking the absolute value for this difference):

$\\ \lvert 68-70.7 \rvert = \lvert 70.7-68 \rvert\;in = 2.7\;in$ .

That is, <em>the positive difference is 2.7 in</em>.

b. How many standard deviations is that [the difference found in part (a)]?

To find how many <em>standard deviations</em> is that, we need to divide that difference by the <em>population standard deviation</em>. That is:

$\\ \frac{2.7\;in}{2.3\;in} \approx 1.1739 \approx 1.174$

In words, the difference found in part (a) is 1.174 <em>standard deviations</em> from the mean. Notice that we are not taking into account here if the raw score, <em>x,</em> is <em>below</em> or <em>above</em> the mean.

c. Convert Nelson's height to a z score.

Using formula [1], we have

$\\ z = \frac{x - \mu}{\sigma}$

$\\ z = \frac{68\;in - 70.7\;in}{2.3\;in}$

$\\ z = \frac{-2.7\;in}{2.3\;in}$

$\\ z = -1.1739 \approx -1.174$

This z-score "tells us" that Nelson's height is <em>1.174 standard deviations</em> <em>below</em> the population mean (notice the negative symbol in the above result), i.e., Nelson's height is <em>below</em> the mean for heights in the club presidents of the past century 1.174 standard deviations units.

d. If we consider "usual" heights to be those that convert to z scores between minus2 and 2, is Nelson's height usual or unusual?

Carefully looking at Nelson's height, we notice that it is between those z-scores, because:

$\\ -2 < z_{Nelson} < 2$

$\\ -2 < -1.174 < 2$

Then, Nelson's height is <em>usual</em> according to that statement.

7 0

3 years ago

Rhian sat a math test and an english test.In the maths test she scored 14 out of 17.In the english test she scored 31 out of 39.

Dvinal [7]

Answer:

The maths test

Step-by-step explanation:

If you convert both of the results to percentage,

Maths:

$\frac{14}{17} \times 100 = 82\%$

English:

$\frac{31}{39} \times 100 = 79\%$

You'll see that she scored better in the maths test.

4 0

3 years ago