the value of a 8 in the ten millions place is what fraction of the value of a 8 in the hundred million place

Mathematics

1 answer:

Shalnov [3]3 years ago

6 0

Was this supposed to be a question? =|

You might be interested in

A study on how circus ticket pricing influences ticket sales shows that there is an average increase of 4 people for every $3 de

____ [38]

Let the price of a ticket be originally T dollars, and the number of clients be N.

let the price decrease by x 3-dollars.

"there is an average increase of 4 people for every $3 decrease on the price of the ticket."

means:

if the price is decreased by 1-3$:
then N become N+4, and T becomes T-3

if the price is decreased by 2-3$:
then N become N+4+4=N+2*4, and T becomes T-3-3=T-2*3

So if the price is decrease by x-3 dollars:

N becomes N+4x, and T becomes T-3x

"A circus owner sells an average of 340 tickets when the price of a ticket is $75."

In this case N=340, and T=75$

If the owner does not change the price ticket, x=0, the revenue is 340*75,

If the owner decreases the price of the tickets by x-3$, then the revenue will be
(N+4x)(T-3x)=(340+4x)(75-3x) dollars,

If R is the function of the revenue depending on x, then

R(x)=(340+4x)(75-3x) dollars

Answer: R(x)=(340+4x)(75-3x) dollars

8 0

3 years ago

Solve the differential equation.<br><br> (y^2 + xy^2)y' = 1

stira [4]

$(y^2 + xy^2)y' = 1 \ \Rightarrow\ (y^2 + xy^2)\frac{dy}{dx}= 1 \ \Rightarrow\\ \\
y^2(1 + x) \frac{dy}{dx} = 1 \ \Rightarrow\ y^2 dx = \frac{dx}{1 + x}\ \Rightarrow \\ \\
\int y^2 dx =\int \frac{dx}{1 + x} \ \Rightarrow\ \frac{1}{3}y^3 = \ln|1+x| + C\ \Rightarrow \\ \\
y^3 = 3 \ln|1 + x| + 3C\ \Rightarrow\ y = \sqrt[3]{3\ln|1+x| + K},\ \text{where $K = 3C$}
$