<span> (a) if 1 woman is randomly selected, find the probability that her height is less than 64 in
using z-score formula:
z-score=(x-mu)/sig
(64-63.5)/2.8
=0.18
thus
P(x<64)=P(z<0.18)-=0.5714
B] </span><span> if 33 women are randomly selected, find the probability that they have a mean height less than 64 in
using the central limit theorem of sample means, we shall have:
2.8/</span>√33=0.49
since n>30 we use z-distribtuion
z(64)=(64-63.5)/0.49=1.191
The
P(x_bar<64)=P(x<1.191)=0.8830
Answer:
x=10, y=-1
Step-by-step explanation:
x-y=11
2x+y=19
3x=30
x=10
10-y=11
-y=1
y=-1
USED ELIMINATION BC THERE WAS ALREADY A Y AND -Y
12.28 = 12 and 28 hundredths so its 12
Hope I helped!
