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Trava [24]
3 years ago
13

Directions: Using only numbers 1-6 (and only once per inequality), fill in the boxes to create a true statement with the smalles

t possible interval:

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

1.40

Step-by-step explanation:

√2=1.41

So, the smallest possible interval will be 1.40 and 1.42

√3=1.73

So, the smallest possible interval will be 1.72 and 1.74

√4=2.00

So, the smallest possible interval will be 1.99 and 2.01

√5=2.24

So, the smallest possible interval will be 2.23 and 2.25

√6=2.45

So, the smallest possible interval will be 2.44 and 2.46


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An arithmetic sequence (a_n) is as follows:

a_1\\a_2=a_1+d\\a_3= a_1+2d\\a_4=a_1+3d,... where a_1 is the first term and d is the constant difference, 

thus, we see that the n'th term of an arithmetic sequence is a_n=a_1+(n-1)d


in our particular case d=5, the third term is 8, so we have:

a_3=8=a_1+2\cdot5\\\\8=a_1+10\\\\a_1=-2


and the general term is a_n=-2+5(n-1),


Answer: first term is -2, n'th term is -2+5(n-1)


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Step-by-step explanation:

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