Answer:
Step-by-step explanation:
We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).
First, recall that the equation of a circle is given by:
Where (<em>h, k</em>) is the center and <em>r</em> is the radius.
Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:
Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:
Solve for <em>r: </em>
<em />
<em />
Simplify. Thus:
Finally, add:
We don't need to take the square root of both sides, as we will have the square it again anyways.
Therefore, our equation is:
They live 9 3/4 blocks away from eachother
32000 and 500 , so the number 32000 has three 0 and 500 2 , so you can take off two 0 from 32000, which equals to 320 .You have to find a number that times 5 equals 320 or almost , the most approaching number is 6 , because 5 times 6 equals 30 , then you have to subtract, the result of the subtraction is 2 , 2 is less than 5 so we have to put a zero , so we got 20 , which number times 5 can give you 20 ? , 4 , so your answer is 64 .
Answer:
Step-by-step explanation:
Hint: 1- 2sin²x = Cos 2x
LHS = 1 - 2Sin² (π/4 - Ф/2)
= Cos 2 *(π/4 - Ф/2)
= Cos 2*π/4 - 2*Ф/2
= Cos π/2 - Ф
= Sin Ф = RHS
Side BC is congruent to side BC.
Using the congruent angles and the angle bisectors, you can get two angles congruent to two other angles, so you use ASA to prove the triangles congruent. Then you use CPCTC to prove the sides congruent.
Answer: C.) ASA
