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noname [10]
2 years ago
9

Plz guys help me plz

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
6 0

i hope this helps- im not sure if its correct or not

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If line a is perpendicular to line b and the slope of line a is 7 whats the slope of line b
amm1812

Answer:

If a line is perpendicular to another line, that means that the slope is completely opposite that of the original line.  The first thing that we do to the slope is we negate the number which means that if we have a slope of -7 our slope because 7 in this step.  In our case our slope is 7 so in this step it becomes -7.

Moving onto the second part which is to get the reciprocal of the number which means that if we have \frac{1}{2} then we would switch it to 2.  In our case our number is -7 so we would make that into a fraction like this -\frac{1}{7}.

In conclusion, our final slope of the perpendicular line is -\frac{1}{7}.

<u><em>Hope this helps!  Let me know if you have any questions</em></u>

8 0
2 years ago
Read 2 more answers
What transformations can be used to show two figures are congruent?
Zinaida [17]
Translation rotation reflection
7 0
3 years ago
The triangles are congruent by
hichkok12 [17]

...........

Step-by-step explanation:

ASA, AAS and SAS

3 0
3 years ago
Are the graphs of each pair of equations parallel, perpendicular, or neither? x = 4 and y = 3
levacccp [35]

Answer:

perpendicular

Step-by-step explanation:

The graph of x = 4 is a vertical line and the graph of y = 3 is a horizontal line.

Vertical and horizontal lines are perpendicular.

3 0
3 years ago
What is tan theta when csc theta =2 sqrt 3?
Slav-nsk [51]

Answer:

\displaystyle \tan\theta=\frac{\sqrt{11}}{11}

Step-by-step explanation:

<u>Trigonometric Identities</u>

If the trigonometric function value of an angle is given, we can find the rest of the trigonometric values of the angle by using one or more of the fundamental identities.

To solve this problem, we need to use the following identities:

\displaystyle \cot^2\theta=\csc^2\theta-1

\displaystyle \tan\theta=\frac{1}{\cot\theta}

Since we are given:

\displaystyle \csc\theta=2\sqrt{3}

And the angle is in the first quadrant, calculate the cotangent:

\displaystyle \cot^2\theta=(2\sqrt{3})^2-1

\displaystyle \cot^2\theta=4*3-1=11

\displaystyle \cot\theta=\sqrt{11}

The tangent is:

\displaystyle \tan\theta=\frac{1}{\sqrt{11}}

Rationalizing the denominator:

\displaystyle \tan\theta=\frac{1}{\sqrt{11}}*\frac{\sqrt{11}}{\sqrt{11}}

\boxed{\displaystyle \tan\theta=\frac{\sqrt{11}}{11}}

7 0
3 years ago
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