Answer:
SSS is the congruence theorem that can be used to prove Δ LON is congruent to Δ LMN ⇒ 1st answer
Step-by-step explanation:
Let us revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles and one side in the 2nd Δ
- HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right Δ
In triangles LON and LMN
∵ LO ≅ LM ⇒ given
∵ NO ≅ NM ⇒ given
∵ LN is a common side in the two triangles
- That means the 3 sides of Δ LON are congruent to the 3 sides
of Δ LMN
∴ Δ LON ≅ LMN ⇒ by using SSS theorem of congruence
SSS is the congruence theorem that can be used to prove Δ LON is congruent to Δ LMN
Answer:
Exact volume is 216π in^3.
Step-by-step explanation:
If B is the radius of the base of the cylinder then the volume is:
V = πr^2h
= π * 6^2 * 6
= π*36*6
= 216π in^3.
Hey there!!
Given equation :
... 5(3m – 2n) –2(m – 2n)
Applying the distributive property :
... 15m - 10n - 2m + 2n
Combining like terms :
... 13m - 8n
Hope my answer helps!!
You have 1/7 divided by 3. And you should know that you can multiply by the reciprocal. Put a 1 over the 3 to get 1/3.
1/7 x 1/3 = 1/21
