Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:

Step-by-step explanation:
Eliminating a negative and changing our operation

Rewriting our equation with parts separated

Solving the whole number parts

Solving the fraction parts
![-\frac{5}{6} +\frac{1}{4} =[?]](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D%20%2B%5Cfrac%7B1%7D%7B4%7D%20%3D%5B%3F%5D)
Find the LCD of 5/6 and 1/4 and rewrite to solve with the equivalent fractions.
LCD = 12

Combining the whole and fraction parts

[RevyBreeze]
Answer: The commission is paid according to sales amounts that are likely to vary from month to month.
Step-by-step explanation: Instead of a salary that is paid in the same amount on a schedule, the commission may be very large one month and very small or zero at other times.
Financial planning usually includes monthly payments that and predictable expenses for food, transportation, utilities, etc. The person who earns a commission must remember to set aside some of the "extra" to cover these expenses. And be prepared to work more or harder at some times to make sales when they don't come easily.
3/5 is the answer.
Explanation:
Easy way is make them into decimals, then divide.
So 3/10 = .3
And 2/4 = .5
So .3/.5 = .6
Or 6/10 = 3/5
Hope this helps! Also nice zenitsu pfp