The area of a square is 144 square meters. what is the length in meters of one side of the square?
2 answers:
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Answer:
0.5(x)(x + 2) = 24 (A)
x² + 2x – 48 = 0 (D)
x² + (x + 2)² = 100 (E)
Question:
A question related to this found at brainly (ID:4482275) is stated below.
The area of the right triangle shown is 24 square feet. Which equations can be used to find the lengths of the legs of the triangle? Check all that apply.
0.5(x)(x + 2) = 24
x(x + 2) = 24
x2 + 2x – 24 = 0
x2 + 2x – 48 = 0
x2 + (x + 2)2 = 24
Step-by-step explanation:
Find attached the diagram.
Area of triangle = ½ × base × height
= 0.5×b×h
base= x ft
Height = (x+2) ft
Area = 24ft²
24 = 0.5(x)(x+2)
0.5(x)(x + 2) = 24 (A)
The equations that can be used to find the lengths of the legs of the triangle must be equivalent to 0.5(x)(x + 2) = 24
On expanding this: 0.5(x)(x + 2) = 24
0.5(x²+2x) = 24
b) x(x + 2) = 24
x(x + 2) is not equal to 0.5(x²+2x)
c) x² + 2x – 24 = 0
0.5(x²+2x) = 24
0.5x²+x - 24 = 0 is not equal to x²+2x- 24 = 0
d) x² + 2x – 48 = 0
0.5(x)(x + 2) = 24
½(x)(x + 2) = 24
x² + 2x = 2(24)
x² + 2x – 48 = 0
Correct option (D)
x² + (x + 2)² = 100
x² + x² + 4x + 4 = 100
2x² + 4x = 96
2(x² + 2x +48)= 0
x² + 2x +48 = 0 is equal to 0.5(x²+2x) = 24
Correct (E)
Let's see what to do buddy...
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The sum of the angles of each n-sided figure is found in the following equation :
The question's figure is 5-sindes figure
so the sum the angles equal :
So we have :
Subtract the sides of the equation minus 479
And we're done.
Thanks for watching buddy good luck.
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